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Old 09-10-2014, 02:54 PM   #9861
Cing Krimson
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Hey, how do I differentiate:

x^2+3x+3/x+1 ?
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Old 09-10-2014, 03:06 PM   #9862
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Differentiate each one separately and then sum them up.
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Old 09-10-2014, 03:08 PM   #9863
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= x^2 + 3(x+1)/(x+1) = x^2 + 3

d(x^2 + 3)/dx = 2x
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Old 09-10-2014, 03:15 PM   #9864
Cing Krimson
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I thought the x^2 and the 3 would still need divided by x+1 after that Jam... Or am I wrong?
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Old 09-10-2014, 03:19 PM   #9865
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Quote:
Originally Posted by Cing Krimson
Hey, how do I differentiate:

x^2+3x+3/x+1 ?


D(x^2) + D(3x) + D(3/x) + D(1)
= 2x + 3 - 3/x^2 + 0
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Old 09-10-2014, 03:21 PM   #9866
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Wait, was it all in a fraction? I assumed it was (x^2) + (3x) + (3/x) + 1 because that's the conventional order of operations.

Jam assumed it was (x^2) + (3x+3)/(x+1).

I'm guessing it's (x^2+3x+3)/(x+1) ?
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Old 09-10-2014, 03:24 PM   #9867
Cing Krimson
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it's all divided by x+1, sorry that wasn't clear
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Old 09-10-2014, 03:33 PM   #9868
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(x^2+3x+3)*(x+1)^(-1)

Now use product rule along with chain rule. Do you know how to do that?
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Old 09-10-2014, 03:33 PM   #9869
Cing Krimson
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It's quotient rule isn't it? I think I'm getting confused because I missed a bit in class with the x^2 being on top, I think I got it now though.
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Old 09-10-2014, 03:35 PM   #9870
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Yeah you can use quotient rule but I forgot that rule and usually just move the fraction up like I did. One less thing to remember.

It also helps to have somewhat of an understanding of what's going on then just following a rule in case you make a small mistake in remembering or reading the rule.
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Old 09-10-2014, 03:40 PM   #9871
Cing Krimson
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Yeah I missed the first month of the course, and this was part of what I missed. It shouldn't take too long to know whats going on though hopefully
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Old 09-10-2014, 03:40 PM   #9872
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Quote:
Originally Posted by Cing Krimson
it's all divided by x+1, sorry that wasn't clear

Use some ffing brackets.

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