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Old 03-28-2014, 05:08 AM   #1
GaryBillington
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Maths question for y'all

Here's the thing: a * b * c

Sounds easy?

Here's the hard part:

a must equal between 4 and 32
b must equal between 15 and 9999
c must equal between 1 and 50

The answer must be 5,000,001.

Go....
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Old 03-28-2014, 05:39 AM   #2
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are decimals allowed?
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Old 03-28-2014, 05:43 AM   #3
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10.0010021002andsomemorethatcalculatorwouldn'tshow
9999
50
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Old 03-28-2014, 05:43 AM   #4
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Quote:
Originally Posted by Cianyx
are decimals allowed?

No, sorry!
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Old 03-28-2014, 05:44 AM   #5
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Old 03-28-2014, 05:44 AM   #6
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Quote:
Originally Posted by GaryBillington
No, sorry!

well shit.
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Old 03-28-2014, 05:44 AM   #7
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lol fuck that, I'm on sprang breayuk
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Old 03-28-2014, 06:00 AM   #8
GaryBillington
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Quote:
Originally Posted by moody git
well shit.

Yep

Quote:
Originally Posted by Cianyx

The network where I work doesn'[t let me go there! (It usually blocks images too otherwise I'd ask for a screenshot)

Actually, I'm always kind of surprised it lets me get to UG forums, most other forums I use are blocked too - the network guys have the net pretty well locked down.
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Old 03-28-2014, 06:03 AM   #9
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Quote:
Originally Posted by Cianyx



Wrong, because it has to have these rules as stated in OP

Quote:
a must equal between 4 and 32
b must equal between 15 and 9999
c must equal between 1 and 50


For the record, that site says 5000001 = 3 x 47 x 35461
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Old 03-28-2014, 06:04 AM   #10
Dregen
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Quote:
Originally Posted by Cianyx


this website is magical

Quote:
Originally Posted by BjarnedeGraaf
Wrong, because it has to have these rules as stated in OP



For the record, that site says 5000001 = 3 x 47 x 35461


derp

Last edited by Dregen : 03-28-2014 at 06:07 AM.
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Old 03-28-2014, 06:10 AM   #11
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Quote:
Originally Posted by BjarnedeGraaf
Wrong, because it has to have these rules as stated in OP



For the record, that site says 5000001 = 3 x 47 x 35461

30 x 3546.1 x 47

happy?
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Old 03-28-2014, 06:16 AM   #12
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Quote:
Originally Posted by Diamond Dave
30 x 3546.1 x 47

happy?


TS said no decimals

TBH I'm not sure if it's possible with the rules laid out by TS.
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Old 03-28-2014, 06:18 AM   #13
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Well I only looked at the OP
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Old 03-28-2014, 06:23 AM   #14
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2+2=4
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Old 03-28-2014, 06:30 AM   #15
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The answer is 5,000,001
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Old 03-28-2014, 06:33 AM   #16
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25.

And the car and the person will hit the ground at the same time.
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Old 03-28-2014, 07:00 AM   #17
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32x6250x25=5,000,000

Is that not close enough?


EDIT 5,000,331 (21x7681x31)

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Old 03-28-2014, 07:02 AM   #18
Dregen
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if you trust my C programming skills (very little, tbh. i know how to use 'for' statements though) then you can safely conclude it isn't possible using those given numbers

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Old 03-28-2014, 07:07 AM   #19
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Quote:
Originally Posted by BjarnedeGraaf
Wrong, because it has to have these rules as stated in OP



For the record, that site says 5000001 = 3 x 47 x 35461

It isn't wrong. Those are distinct prime factors. That is the only way you can write that number as a multiple of three other numbers. Those conditions are impossible to meet.

These kind of problems aren't "hard". All you need is the prime factorization of a number.

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Old 03-28-2014, 07:58 AM   #20
GaryBillington
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Quote:
Originally Posted by bass-fale47
32x6250x25=5,000,000

Is that not close enough?

Already got a few examples for 5,000,000
Quote:
Originally Posted by BjarnedeGraaf
TBH I'm not sure if it's possible with the rules laid out by TS.

Quote:
Originally Posted by MakinLattes
Those conditions are impossible to meet.

Quote:
Originally Posted by Dregen
if you trust my C programming skills (very little, tbh. i know how to use 'for' statements though) then you can safely conclude it isn't possible using those given numbers


You're most likely right. I've been experimenting with different options for a few days now & haven't found anything. My development team haven't found a way to replicate that result either. Asking the internet was a bit of a final resort to try & beat my team! I had no idea if it's possible or not.

The thing is, it's to test a requirement put on the software we're developing that the maximum result allowed is 5,000,000. It copes with that OK, it copes with numbers significantly higher (like bass-fale47's other option provided), but for an accurate test we should attempt a run of 5,000,001 to prove it fails.

As it isn't possible I'll just have to cover it in my project report
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