darkstar2466

I got (sin(4)/2 - 1/2) - (sin(-4)/2 + 1/2). I think it's right.

EDIT: F*ck, I forgot to change the bounds of integration. Whatever, it would end up right if I redid it.

__________________

Art & Lutherie

guywithguitar

Haha, guys, it's just the area under half of a unit circle, no math involved.

lounge act

I'll be needing this a lot...


You better be telling the truth on the answers!

Cus I sure as hell wouldn't be able to tell if you're lying

__________________
http://www.last.fm/user/andrew692
My Nirvana Group (that I never look at anymore...)

bigwillie

Which also equals 1.571. Which is what I said.

shadowsoldier08

im not quite sure what u mean, if u mean as in y=2, then you would just draw a straight line on the y=2 spaces, i.e. (0,2)(1,2)(-1,2) all the way across, so no matter what the x=?, the y=2 always

__________________
My Gear
Schecter C-1 Hellraiser
Peavey Valveking 112
Line 6 über-Metal Pedal

guywithguitar

Yeah, but you actually did the integral .

Zackie EL

I know, but keep it in radians. Sorry I didn't mention it.

darkstar2466

Anyone done double/triple or flux/circulation integrals here?

__________________

Art & Lutherie

bigwillie

But the long way was much more fun.



Ah well, it's all good.

fluffylump2

y = x+2

your slope is 1/1, and your y-intercept is (0,2). So start at that point and move up one and over one. Plot that point. then move up one and over one. and plot that point. you'll soon see what the line is supposed to look like.

guywithguitar

I've had one double integral problem ever, and was kind of walked through it, but I think I understand how to do them. But do elaborate on the flux and circulation integrals
.

bigwillie

I've done a few triples, but I've never heard of the flux/circulation integrals before either.

Zackie EL

Ok here's another easy one. This is trig.

Give me the area of a triangle with sides a-9.12, b-4.67, c-10.83 and tell me how you did it.

darkstar2466

Flux is the amount of flow over a certain space, so you're usually given a scalar quantity and you integrate over that region to the flow from it. It's usually used for electricity and magnetism. Here's the basic form:



Circulation is similar, except it's over a closed loop and you figure out the integral of the velocity of a fluid or something circulating. Here's the basic form for that:



But before you do that, you must learn line integrals, which is the basis of these.

__________________

Art & Lutherie

guywithguitar

Ah, I'm taking E&M next semester, a.k.a. about a week from now, so I'll be familiar with those soon .

darkstar2466

Yea, you should hit these pretty soon. The math series I'm taking does this first, to prepare for E&M, I guess.

What math are you taking?

__________________

Art & Lutherie

Zoso92

im a dumbass when it comes to math

n science


n all school stuff
















i like music class tho that count?

Zackie EL

No answers?

darkstar2466

Uh, I think I would use law of cosines to get the angle C, facing the hypotenuse c, then I would use the general formula of the triangle area A = 1/2 a * b * sin(C). I don't feel like plugging in the numbers.

__________________

Art & Lutherie