UG Community @ UltimateGuitar.Com

Profile
History


01022013, 10:35 AM  #9181 
Used Register
Join Date: Oct 2008
Location: UK/NO

How do you rearrange:
v = 1 + bx + cx² to get a straight line?
__________________
ERROR 0x45: Signature not found

01072013, 06:25 PM  #9182  
stealing human bones
Join Date: Apr 2011

When doing linear equations, how would you write the equation for a vertical line?
__________________
Quote:
Quote:
Quote:


01072013, 07:25 PM  #9183  
I'm too old for this ****
Join Date: Oct 2007
Location: OH

Quote:
x=something
__________________
██████████████████████████
██████████████████████████ ██████████████████████████ ██████████████████████████ ██████████████████████████ ██████████████████████████ ██████████████████████████ LET'S GO BUCKS 

01072013, 07:28 PM  #9184  
Registered User
Join Date: Feb 2007

Quote:
x = constant, much like y = constant is a horizontal line!
__________________
"In the beginning the Universe was created. This has made a lot of people very angry and been widely regarded as a bad move." 

01122013, 03:27 AM  #9185 
UG's Black Queen
Join Date: Sep 2009
Location: Poking in the pile

I have just started integration and I'm still a little confused... how would you integrate this?
(square root of x  1/x)^2
__________________
Signatureless. And this doesn't count. Because I said so. 
01122013, 03:31 AM  #9186 
fully retractable
Join Date: Mar 2007
Location: { }

Is the entire square root being squared?

01122013, 06:55 AM  #9187  
UG's Black Queen
Join Date: Sep 2009
Location: Poking in the pile

Quote:
Ok yeah that wasn't very clear... it's [(square root of x)(1/x)]^2
__________________
Signatureless. And this doesn't count. Because I said so. Last edited by sherry07 : 01122013 at 06:57 AM. 

01122013, 07:07 AM  #9188 
fully retractable
Join Date: Mar 2007
Location: { }

So (√(x)  1/x)^2.
Foil and simplify: (√(x)  1/x)(√(x)  1/x) = √(x)^2  2(√(x)/x) + 1/x^2 = x  2x^(1/2) + x^2. So for the indefinite integral we have ∫ x  x^(1/2) + x^2 dx = ∫x dx  ∫2x^(1/2) dx + ∫x^2dx = (1/2)x^2  4x^1/2  x^1 + C Last edited by MakinLattes : 01122013 at 07:08 AM. 
01132013, 06:37 AM  #9189 
Used Register
Join Date: Oct 2008
Location: UK/NO

How do you find a dy/dx expression when:
sin(xy) = y + x ?
__________________
ERROR 0x45: Signature not found

01132013, 06:58 AM  #9190  
Feminist
Join Date: Feb 2006

Quote:
Implicity differentiation dy/dx=Fx/Fy, so take the sin to the right and simply partial differentiste to x and y.
__________________
Quote:
ಠ_ಠ 

01132013, 07:31 AM  #9191 
Used Register
Join Date: Oct 2008
Location: UK/NO

Thank you!
The answer key just said: (to a simlar question; there's no answer key for exam sets) 1. sin(xy) = x 2. [x(dy/dx) + y] cos(xy) = 1 3. (dy/dx)=[(cos(xy))^1  y] / x Though the method you mentioned yielded the same answer on that question. I'm curious about what happens between step 1. and 2. here...
__________________
ERROR 0x45: Signature not found
Last edited by sfaune92 : 01132013 at 07:39 AM. 
01132013, 08:49 PM  #9192  
up the hoods
Join Date: Jun 2007
Location: Bangor, Norn Iron/Manchester

Quote:
cos(xy)[xdy/dx+y]=dy/dx+1 dy/dx(xcos(xy)1)=1ycos(xy) dy/dx=(1ycos(xy))/(xcos(xy)1) 

01142013, 08:50 AM  #9193 
° ͜ ͡°
Join Date: Sep 2008
Location: London

Hey guys, doing a computing report and was wondering if there's a way to get the convergence of this series for different values of a? Is there a way to express this limit in terms of a? I'm still not great with just plucking limits out of thin air
Any help is appreciated!
__________________
       
When I think of the perpetual journey through life When it always feels like autumn The wind moves slowly to the north And the flowers die Rain falls in my dreams         
01142013, 09:50 AM  #9194 
x'; DROP TABLE *; 
Join Date: Sep 2006
Location: Glasgow.

Sorry, this is a really stupid question but I'm having a hard time visualising this question in my head. Can anyone explain it to me a little better?
A pendulum with a cord length, r=0.5m, swing on a vertical plane. When the pendulum is in the 2 horizontal positions of theta=90' and theta=270', its speed is 5.00ms^1 
01142013, 11:20 AM  #9195  
° ͜ ͡°
Join Date: Sep 2008
Location: London

Quote:
Imagine the pendulum upside down, completely vertical, with the weight at the top  this is with θ = 0°. Now rotate it clockwise 90°, that's the first horizontal position, and the other is, yeah, 270°. It's saying that each time θ=90°, v (instantaneous speed) is 5m/s. ...what's the actual question though? :p Quote:
Dayum that looks pretty fascinating... Are you in 3rd year or something? I've seen some stuff about this in IOP news, I never understand anything in physics news though
__________________
       
When I think of the perpetual journey through life When it always feels like autumn The wind moves slowly to the north And the flowers die Rain falls in my dreams         Last edited by papershredder : 01142013 at 11:23 AM. 

01162013, 06:43 AM  #9196 
Used Register
Join Date: Oct 2008
Location: UK/NO

I've got a simple stats question...
So I've calculated mean, variance, standard deviation, and standard error of the mean. How do I find "the 70% confidence limit for the true value"? EDIT: Another question... How do you linearise this: t² = (d² + 4h²) / v² Given that t: dependent variable d: independent variable h: constant v: constant (Or is it possible to have v² as a function of d²?)
__________________
ERROR 0x45: Signature not found
Last edited by sfaune92 : 01162013 at 12:36 PM. 
01162013, 01:15 PM  #9197  
° ͜ ͡°
Join Date: Sep 2008
Location: London

Quote:
I was taught something about a 67% confidence level, I'm assuming this is the same thing  if you have your standard deviation s then the error on your average value (at the 67% confidence level) should be s/sqrt(N) where N is the number of values used to calculate the standard deviation. And I'm not really sure what that second question is asking is that something to do with taking the first order of the Taylor expansion?
__________________
       
When I think of the perpetual journey through life When it always feels like autumn The wind moves slowly to the north And the flowers die Rain falls in my dreams         Last edited by papershredder : 01162013 at 01:17 PM. 

01162013, 01:30 PM  #9198 
Used Register
Join Date: Oct 2008
Location: UK/NO

Thank you.
Also, the second part seems to be asking of t as a function of d. I don't think series has anything to do with it as it is not included in that module. I tried using logs as well, but it didn't go over to well because of that annoying plus on top of the denominator. Regarding your question on the previous page, is it based on a binomial series?
__________________
ERROR 0x45: Signature not found

01162013, 11:20 PM  #9199 
° ͜ ͡°
Join Date: Sep 2008
Location: London

Well can't you just square root it? t = (d+2h)/v ?
which is essentially t = (1/v)d + (2h/v) in straight line form and uh, my question was finding the limit/convergence of that series, in terms of a :/ still stuck on it lol, need to finish writing the report by sunday :'(
__________________
       
When I think of the perpetual journey through life When it always feels like autumn The wind moves slowly to the north And the flowers die Rain falls in my dreams         
01162013, 11:39 PM  #9200 
Lazy Physicist
Join Date: Sep 2008
Location: Tampa

You can't square root it because those values are squared independently and then added. To linearize it you have to get both the dependent and independent variables to a power of 1, but I'm not actually sure how to do that for that problem (been through calc 3 and math methods, I'm ashamed of myself).
What class is that question for? 
Thread Tools  Rate This Thread  



Forum Archives / About / TOS / Advertise with us / Customer Support / UltimateGuitar.Com © 2016
Powered by: vBulletin Version 3.0.9 Copyright ©2000  2016, Jelsoft Enterprises Ltd. 