So I have an geometry report due tomorrow, and it's about the Golden Ratio. I've worked all day and got most of it done. There's only one part I need to do. I must prove mathematically the exact value of the Golden ratio.
I have this link,
http://library.thinkquest.org/27890/goldenRatio2p.html , but the only thing I don't understand is how to do the cross multiplying and the quadratic formula. I would really like to know how to get the answer to the quadratic step in the link. The steps to get what is said in the third step.

I hate homework help threads to, but I'm desperate. Any help is welcome!!
I usually wouldn't be in this situation and ask you guys, but many of you seem very knowledgeable.
Thanks in advance!
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Last edited by OzarkMDaredevil at Dec 1, 2008,
next time don't wait until the last day. >_>

aside from that bit of advice, i really cant help you.
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poor guy

wish i could help
a report? like and Essay? how many words/pages? Moar info pls!

Edit: Sorry read your post again, doesn't really help.
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Its strange that I'm in college doing calc almost everyday, but give me old geometry stuff and I have a hell of a time remembering stuff like this.

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All I need to do is prove it algebraically, no page number. I just need to do a 'paragraph proof' to prove it. Using **** like hence, therefore...Etc.
What I would ultimately like to know is how to get the whole quadratic formula and cross multiplying from the link in the original post.
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Substitute 1 for X

y*y=y^2
y*-1=-y
1*1=1
therefore 1=y^2-y
subtract 1 from each side, you get the quadratic equation 0=y^2-y-1
use the quadratic formula

Hope that helped

EDIT: wait , do you need to know how to get to cross multyplying?
Quote by DartS17
Substitute 1 for X

y*y=y^2
y*-1=-y
1*1=1
therefore 1=y^2-y
subtract 1 from each side, you get the quadratic equation 0=y^2-y-1
use the quadratic formula

Hope that helped

EDIT: wait , do you need to know how to get to cross multyplying?

I need to know what the Quadratic formula is and how he got from this

To this

Thanks for your help though.
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Last edited by OzarkMDaredevil at Dec 1, 2008,
K just gimme a few minutes, I'll get my old math notes and see if i can help some more

EDIT: Couldn't find ****, but looks like he can help\/\/\/
Last edited by DartS17 at Dec 1, 2008,
the quadratic formula:

-b +/- sqrt. b^2 -4ac
_______________
2a

soooo

a = 1
b = -1
c = -1

so he's got

- -1 +/- sqrt. -1^2 - 4x1x-1
_____________________
2x1

and that is equal to the things that he got, i think you'll find.

edit:

1 + sqrt. (5)
__________
2

and

1 - sqrt. (5)
___________
2

yeah, it works perfectly

hope you get your work done.

edit again:

its difficult to type the quadratic formula. if you were to say it to someone, it would sound like this:

"minus B, plus OR minus the square root of B squared minus four A C divided by two A"

so, the bit where it says +/-, that means that theres two solutions, the positive and negative roots will give them both.
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Last edited by instagata0 at Dec 1, 2008,
You two are absolute life savers. I am eternally grateful to you. I will suck you off or give you money or virgins or something. Thank you very much!!!!!!!!!!!!!!!!!!!!!!!! I got it done! **** YES!!!
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