#1

what is the longest trigonometric identity functions you can make?

example

sin^2(theta) + cos^2(theta) = 1

but like a really long one

longer than

1 + cot^2(theta) - cos^2(theta) - cos^2(theta)*cot^2(theta)

after you simplify you find it equals one

example

sin^2(theta) + cos^2(theta) = 1

but like a really long one

longer than

1 + cot^2(theta) - cos^2(theta) - cos^2(theta)*cot^2(theta)

after you simplify you find it equals one

#2

what is the longest trigonometric identity functions you can make?

example

sin^2(theta) + cos^2(theta) = 1

but like a really long one

longer than

1 + cot^2(theta) - cos^2(theta) - cos^2(theta)*cot^2(theta)

after you simplify you find it equals one

It can be infinitely long.

sin^2(theta) + cos^2(theta) - cos^2(theta) + cos^2(theta) = 1

#3

It can be infinitely long.

sin^2(theta) + cos^2(theta) - cos^2(theta) + cos^2(theta) = 1

thats too easy! im trying to stump my teacher . but i get what your doing. that inspires me. thanks

#4

thats too easy! im trying to stump my teacher . but i get what your doing. that inspires me. thanks

That's all any equation is that can be simplified. Just keep adding to it, but make sure you add in small stages that keep the equation balanced.

#5

what math class do you have? Mine is too easy... multiplying (4x)^3

its lame, i need to be challanged.

But yeah.... it can be infinitely long as long as you balance it out

its lame, i need to be challanged.

But yeah.... it can be infinitely long as long as you balance it out

#6

i was hoping someone had one that was intense that they could give me cause im lazy. but im working on it and so far its pretty cool

#7

i was hoping someone had one that was intense that they could give me cause im lazy. but im working on it and so far its pretty cool

I seriously doubt that.

All you need is http://www.sosmath.com/trig/Trig5/trig5/trig5.html and then half-angle formulas too