Ok, so I have a pre-calculus exam tomorrow, and I don't know how to solve inverse functions, which is going to be a big chunk on it. Someone please explain...
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ok solving inverse functions like lets say Y= x^2 plus 2

really simple function.

instead of solving for y solve for x. and then switch the variables again.

so the inverse function would be Y=square root of(X+2)

steps:

1. Y=x^2-2

2.Y+2=x^2

3. square root of(y+2) = x

4. then switch variables and square root of(x+2)=Y
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Quote by FishCream
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1)to find the inverse of a function, make the x and y switch spots.

Y<SUP>2</sup>=(x-3)<sup>2</sup>-4

to

X<SUP>2</sup>=(y-3)<SUP>2</sup>-4

2) SOlve for y

X<SUP>2</sup>=(y-3)<SUP>2</sup>-4

x+4<SUP>2</sup>=(y-3)<SUP>2</sup>
_________________ _______________
v (x+4)<SUP>2</sup>=v(y-3)<SUP>2</sup

(x+4)=y-3

x+7=y

****the<SUP>2</sup> means squared****

hope that helps