#1

HOW THE **** DO YOU SIMPLIFY THIS??

2 divided by the 6th root of 81

I've been trying to answer this question for about an hour now and I'm just about frustrated to tears right now. Someone please help me

2 divided by the 6th root of 81

I've been trying to answer this question for about an hour now and I'm just about frustrated to tears right now. Someone please help me

#2

Use a calculator

#3

"6th root of 81?" good lord, I'm in pre-calc and I cant figure it out.

#4

Yes.

#5

Use a calculator

+1 plug in 6th root of 81, then just eliminate like terms?

#6

7+11=always open, oh thank heaven. thats the answer, you can thank me later.

#7

#8

The problem is on the test I have tomorrow I'm not allowed to use a calculator. It has to be all in my head.

I'm studying rational exponents right now, if that helps any.

I'm studying rational exponents right now, if that helps any.

#9

Dude, Algebra 2 sucks, doesn't it?

Just one week has half killed me. Sorry though, I don't know what to tell you. We haven't gotten that far yet.

Just one week has half killed me. Sorry though, I don't know what to tell you. We haven't gotten that far yet.

#10

umm, (54 times sixth root of 9) over 81.

I think.

I think.

#11

The problem is on the test I have tomorrow I'm not allowed to use a calculator. It has to be all in my head.

I'm studying rational exponents right now, if that helps any.

Well then use a calculator to figure out the problem for homework and remember the answer. I can't help any more than that, although that sounds way more difficult than anything we've been doing in my algebra 2 class.

#12

2 / (81 ^ (1 / 6))

I suppose you could bring the fraction to the top...

2 * (81 ^ -(1/6))

Which just ends up being 2 * -6th root of 81 ;|

Which isn't exactly a great deal simpler :|

Can't think of what else to do... I've been on holidays for the last month and a bit......

I suppose you could bring the fraction to the top...

2 * (81 ^ -(1/6))

Which just ends up being 2 * -6th root of 81 ;|

Which isn't exactly a great deal simpler :|

Can't think of what else to do... I've been on holidays for the last month and a bit......

#13

I think you solve it by multiplying

Sixth Root of 81

by

Fifth root of 81

Then you just simplify from there.

__2__Sixth Root of 81

by

__Fifth root of 81__Fifth root of 81

Then you just simplify from there.

#14

Alright, thanks for the help guys :/

I guess this will just be another failed test for me.

I'm over ****ing algebra 2

when the hell am I ever going to need know rational exponents in ****ing music?

or even any sort of engineering?

I mean, in my book they always have an "applied to life" section explaining why we need this dumb **** and this section has no trace of it.

I guess this will just be another failed test for me.

I'm over ****ing algebra 2

when the hell am I ever going to need know rational exponents in ****ing music?

or even any sort of engineering?

I mean, in my book they always have an "applied to life" section explaining why we need this dumb **** and this section has no trace of it.

#15

81^(1/6)

EDIT: i don't care what anybody else says, this is the answer. you can even try it on a calculator.

6root81 = 2.080083823

81^(1/6) = 2.080083823

you put the number of the root as the denominator and one as the numerator. that's it. everybody is making it more complex than it needs to be.

EDIT: i don't care what anybody else says, this is the answer. you can even try it on a calculator.

6root81 = 2.080083823

81^(1/6) = 2.080083823

you put the number of the root as the denominator and one as the numerator. that's it. everybody is making it more complex than it needs to be.

*Last edited by SlashYourFug at Jan 13, 2009,*

#16

I'm doing this **** too, I feel your pain man. Can't help you though, thats probably why I have a C- in that class

#17

6th root of 81 is 2.08 if that helps

#18

I don't remember what exactly simplify means anymore, but if I came up to a term like that in the middle of a calc problem and the numbers didn't work, I'd raise both the top and bottom to the 6th power, which would give you 6/81.

Actually, I'm not totally sure you can do that, but it seems natural to me.

Actually, I'm not totally sure you can do that, but it seems natural to me.

#19

I am realively certain that it is

27

__16 times sixth root of 9__27

#20

2*3root(3)

-------------

3

-------------

3

#21

81^(1/6)

Well that explains the denominator.

Now I need to show how it turns into

2 cube root of 3 over 3

#22

(2*rt3)/3

i think

i think

#23

(2*rt3)/3

i think

how did you get that??!

#24

I think you solve it by multiplying2

Sixth Root of 81

byFifth root of 81

Fifth root of 81

Then you just simplify from there.

Actually, that does ring a bell, but you would multiply the fraction by the sixth root of 81 over itself, not the fifth. Then you're pretty much done unless you need to reduce.

Alright, thanks for the help guys :/

I guess this will just be another failed test for me.

I'm over ****ing algebra 2

when the hell am I ever going to need know rational exponents in ****ing music?

or even any sort of engineering?

I mean, in my book they always have an "applied to life" section explaining why we need this dumb **** and this section has no trace of it.

Actually, as an engineering student, I can tell you this stuff does come up later, but only as a tool to do MUCH more complicated math (think one problem takes several pages).

#25

how did you get that??!

6th root of 81 can be expressed as 6 root of (3*3*3*3) or 3rd root of (3^2)

#26

Well that explains the denominator.

Now I need to show how it turns into

2 cube root of 3 over 3

i think i know how to do it, but i'm so damn tired i can't think. sorry man.

#27

i did this:

for 6th root of 81:

sqrt(sqrt(sqrt 81))

=sqrt(sqrt 9)

=sqrt 3

so then u have 2/ sqrt 3, but usually u dont keep a radical in the denominator

so then multiply it by rt3/rt3 (which you can do, cuz it equals 1)

and you get (2*rt3)/3

for 6th root of 81:

sqrt(sqrt(sqrt 81))

=sqrt(sqrt 9)

=sqrt 3

so then u have 2/ sqrt 3, but usually u dont keep a radical in the denominator

so then multiply it by rt3/rt3 (which you can do, cuz it equals 1)

and you get (2*rt3)/3

#28

Actually, that does ring a bell, but you would multiply the fraction by the sixth root of 81 over itself, not the fifth. Then you're pretty much done unless you need to reduce.

Actually, as an engineering student, I can tell you this stuff does come up later, but only as a tool to do MUCH more complicated math (think one problem takes several pages).

I'm just ranting right now.

I know it comes in handy in a specific position in a specific sect of a specific profession.

I'm just super frustrated.

and spoonman, if there was a way to make love to you over the internet, I would do it right about now.

#29

I'm just ranting right now.

I know it comes in handy in a specific position in a specific sect of a specific profession.

I'm just super frustrated.

and spoonman, if there was a way to make love to you over the internet, I would do it right about now.

spoonman = sporkman?

#30

Are you supposed to rationalize the denominator?

I could be wrong, but the answer they're looking for could be...

[2 * 3^(1:3)] : 3

2 : 81^(1:6)

[2 * 81^(1:3)] : [81^(1:6) * 81^(1:3)]

[2 * 81^(1:3)] : 9

[2 * 3 * 3^(1:3)] : 9

[6 * 3^(1:3)] : 9

[2 * 3^(1:3)] : 3

I could be wrong, but the answer they're looking for could be...

[2 * 3^(1:3)] : 3

2 : 81^(1:6)

[2 * 81^(1:3)] : [81^(1:6) * 81^(1:3)]

[2 * 81^(1:3)] : 9

[2 * 3 * 3^(1:3)] : 9

[6 * 3^(1:3)] : 9

[2 * 3^(1:3)] : 3

*Last edited by Dodeka at Jan 13, 2009,*

#31

spoonman = sporkman?

lol yeah

no sleep is taking a toll on me >_>

#32

81^(1/6)

EDIT: i don't care what anybody else says, this is the answer. you can even try it on a calculator.

6root81 = 2.080083823

81^(1/6) = 2.080083823

you put the number of the root as the denominator and one as the numerator. that's it. everybody is making it more complex than it needs to be.

If you gave that answer in a test, you would get 0 marks, sorry.

#33

Well that explains the denominator.

Now I need to show how it turns into

2 cube root of 3 over 3

parentheses please

maybe i can help

i just finished pre-calc last quarter

and ive aced 3 HS algebra classes

#34

If you gave that answer in a test, you would get 0 marks, sorry.

actually he is right

6root81=2.080083823

and

81^(1/6)=2.080083823

because

2.080083823^6=81

and TS

is this what your trying to figure out

2/(6√81) = 2(3√3/3)

or is it

2/(6√81) = [2(3√3)]/3

*Last edited by roarinflames at Jan 13, 2009,*

#35

0.961499714 is the answer

i just googled it

i just googled it

#36

0.961499714 is the answer

i just googled it

im pretty sure thats not right actually

nvm

i think they want it in rational form though

*Last edited by roarinflames at Jan 13, 2009,*

#37

im pretty sure its 2/ 3√(√81)

2/ 3√9

go from there im sure

2/ 3√9

go from there im sure