#1
I can't figure out this one math problem I've got in programming

http://www.sce.carleton.ca/courses/ecor-1606/w09/CourseMaterials/1606w09a2.pdf

there's the link to the problem

Basically I need to find the length x knowing only one length of a triangle and an angle. I need to be able to calculate x in terms of only W, theta and D. Give it a read over and help please

edit: see diagrams 1 and 2 for explanation on W, D and theta
#2
right here's a start point - take me a while though

name the longest submerged side (which is not W obv.) L

you can then use some simple geometry to show cosO=X/L

you can also use the constant volume to work out the volume underwater as a function of just L and O and set that equal to to DW

DW = LW-(W^2(1+tan^2(O))

=> D= L - W(1+Tan^2 O)

now see where you are?
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Last edited by doive at Jan 27, 2009,
#7
haha - i was closer than i realised

form that simple rearrangement to give

x= (D+W(1+tan^2(O))) cosO
OR

x = D CosO +W/CosO

reality check
- units ok
- increase W => increase X
- Increase D => increase x
- increase O => increase in x (since w/cos -> infinity)
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#8
the ONLY math thread?
“Any other day I’d say no, but today I’m gonna go ahead and just say no.”

-Dr. Cox
#9
realise i got my maths wrong anyway - for 1+tan^2 0 should read tanO / 2
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