#1

It's some college algebra...

A shoppoing center has a rectangular area of 40,000 Yd squared. It is enclosed on three sides for a parking lot. The Length is 200 yards more than twice the width. What are the dminesons of the lot.

Sorry for the horrible spelling!!

A shoppoing center has a rectangular area of 40,000 Yd squared. It is enclosed on three sides for a parking lot. The Length is 200 yards more than twice the width. What are the dminesons of the lot.

Sorry for the horrible spelling!!

*Last edited by Nirvana_RATM2 at Jan 28, 2009,*

#2

w=200+l

l*w=40,000

40,000=l(200+l)

I think you can solve from there

edit: I hope this is right. =/

edit2: ooops I ****ed up lemme fix it, there

l*w=40,000

40,000=l(200+l)

I think you can solve from there

edit: I hope this is right. =/

edit2: ooops I ****ed up lemme fix it, there

*Last edited by dubstar92 at Jan 28, 2009,*

#3

What is this? This is the second post in the pit today of someone asking for help with f*ckin math.

Do you really want people on UG telling you answers for your algebra class in college?

Do you really want people on UG telling you answers for your algebra class in college?

#4

x(x+200)=40000

solve for x, then add 200 and you have the other side too...

solve for x, then add 200 and you have the other side too...

#5

Really...THAT is college level math? Wow...

Try some Laplace or Fourier transforms and get back to me.

On a side note: thanks for saying math and not maths. Maths is just plain wrong

Try some Laplace or Fourier transforms and get back to me.

On a side note: thanks for saying math and not maths. Maths is just plain wrong

#6

100 by 400

you needa find two equations andf substitute one back into the other to solve....

edited: noticed the twice then + 200..... i woulda failed

you needa find two equations andf substitute one back into the other to solve....

edited: noticed the twice then + 200..... i woulda failed

*Last edited by metalimaster at Jan 28, 2009,*

#7

w=200+l

l*w=40,000

40,000=l(200+l)

I think you can solve from there

edit: I hope this is right. =/

edit2: ooops I ****ed up lemme fix it, there

But shouldn't L= 2w+200?

#8

That's college-level high school class math. Not college level math.

#9

But shouldn't L= 2w+200?

Yeah, I didn't see that it said "twice" I'm a little tired and my eyes hurt from dooing some pretty involved physics problems.

edit: Oh and I see I reversed length and width, I should probably stop trying to think for the rest of the night.

*Last edited by dubstar92 at Jan 28, 2009,*

#10

So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..

#11

Really...THAT is college level math? Wow...

Try some Laplace or Fourier transforms and get back to me.

On a side note: thanks for saying math and not maths. Maths is just plain wrong

+1. complex fourier transforms are hard as hell. god i hate signal analysis. im confused at why you aren't using SI units at uni. what good is using a system that is different to what everyone else uses. on topic...you need to use simultaneous equations.

#12

So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..

well it's w(200+2w) = 40,000

so distribute the w and you get

200w+2w^2 = 40,000

then quadratic formula

2w^2+200w-40,000=0

I'm sure it factors but you can do that, right?

edit: yeah, that guy below me got it.

*Last edited by dubstar92 at Jan 28, 2009,*

#13

So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..

From there you have (2w+200)*w=40,000

2w^2+200w=40,000

w^2+100w-20,000=0

(w+200)*(w-100)=0

w=100 or -200

since the width cant be negative

**w must be 100**

so L=2(100)+200

**L=400**

Edit:

Joe_k, EE major?

*Last edited by wyldething at Jan 28, 2009,*

#14

Am I the only one who read "A shooping centre has a rectangular . . . ?"

#15

From there you have (2w+200)*w=40,000

2w^2+200w=40,000

w^2+100w-20,000=0

(w+200)*(w-100)=0

w=100 or -200

since the width cant be negativew must be 100

so L=2(100)+200L=400

Edit:

Joe_k, EE major?

Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?

#16

Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?

just subtract the 40,000 from both sides so it creates Ax^2+Bx+C form and you factor it

#17

nah photovoltaic engineering but i have done some electrical engineering stuff.

#18

Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?

Its just subtracting 40,000 from both sides.

Say for example x+5=y

You can say that (x+5)-5=(y)-5 right?

so then that means that x=y-5

After that I just factored out a 2 to make the simplification easier.

BTW, what the hell kind of college is this?

#19

That's college math??

I studied stuff like that when I was... 9?

I studied stuff like that when I was... 9?