#1
It's some college algebra...


A shoppoing center has a rectangular area of 40,000 Yd squared. It is enclosed on three sides for a parking lot. The Length is 200 yards more than twice the width. What are the dminesons of the lot.

Sorry for the horrible spelling!!
Last edited by Nirvana_RATM2 at Jan 28, 2009,
#2
w=200+l

l*w=40,000

40,000=l(200+l)

I think you can solve from there

edit: I hope this is right. =/

edit2: ooops I ****ed up lemme fix it, there
grok it.

SKREAM!

Listen to jazz, it's good for you...
Last edited by dubstar92 at Jan 28, 2009,
#3
What is this? This is the second post in the pit today of someone asking for help with f*ckin math.

Do you really want people on UG telling you answers for your algebra class in college?
Do you feel warm within your cage?

And have you figured out yet -


Life goes by?
Quote by Hydra150
There's a dick on Earth, too
It's you
#5
Really...THAT is college level math? Wow...

Try some Laplace or Fourier transforms and get back to me.


On a side note: thanks for saying math and not maths. Maths is just plain wrong
#6
100 by 400

you needa find two equations andf substitute one back into the other to solve....


edited: noticed the twice then + 200..... i woulda failed
Quote by Bubban
I once had a sudden urge to rape sheep in Scotland after watching CNN, that was pretty freaky.
Last edited by metalimaster at Jan 28, 2009,
#7
Quote by dubstar92
w=200+l

l*w=40,000

40,000=l(200+l)

I think you can solve from there

edit: I hope this is right. =/

edit2: ooops I ****ed up lemme fix it, there


But shouldn't L= 2w+200?
#9
Quote by Nirvana_RATM2
But shouldn't L= 2w+200?

Yeah, I didn't see that it said "twice" I'm a little tired and my eyes hurt from dooing some pretty involved physics problems.

edit: Oh and I see I reversed length and width, I should probably stop trying to think for the rest of the night.
grok it.

SKREAM!

Listen to jazz, it's good for you...
Last edited by dubstar92 at Jan 28, 2009,
#10
So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..
#11
Quote by wyldething
Really...THAT is college level math? Wow...

Try some Laplace or Fourier transforms and get back to me.


On a side note: thanks for saying math and not maths. Maths is just plain wrong


+1. complex fourier transforms are hard as hell. god i hate signal analysis. im confused at why you aren't using SI units at uni. what good is using a system that is different to what everyone else uses. on topic...you need to use simultaneous equations.
#12
Quote by Nirvana_RATM2
So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..

well it's w(200+2w) = 40,000

so distribute the w and you get
200w+2w^2 = 40,000

then quadratic formula
2w^2+200w-40,000=0

I'm sure it factors but you can do that, right?

edit: yeah, that guy below me got it.
grok it.

SKREAM!

Listen to jazz, it's good for you...
Last edited by dubstar92 at Jan 28, 2009,
#13
Quote by Nirvana_RATM2
So if L = 2w+200

you have the equation for the area , LW = Area , length times the width equals the area. So if you replace L wouldn't it be

2w+200 * W = 40,000

I'm lost from there on out..


From there you have (2w+200)*w=40,000

2w^2+200w=40,000
w^2+100w-20,000=0
(w+200)*(w-100)=0
w=100 or -200
since the width cant be negative w must be 100
so L=2(100)+200
L=400

Edit:

Joe_k, EE major?
Last edited by wyldething at Jan 28, 2009,
#14
Am I the only one who read "A shooping centre has a rectangular . . . ?"
Quote by markr17
go eat a hermanpherdite.
#15
Quote by wyldething
From there you have (2w+200)*w=40,000

2w^2+200w=40,000
w^2+100w-20,000=0
(w+200)*(w-100)=0
w=100 or -200
since the width cant be negative w must be 100
so L=2(100)+200
L=400

Edit:

Joe_k, EE major?



Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?
#16
Quote by Nirvana_RATM2
Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?

just subtract the 40,000 from both sides so it creates Ax^2+Bx+C form and you factor it
grok it.

SKREAM!

Listen to jazz, it's good for you...
#18
Quote by Nirvana_RATM2
Ok on w^2+100w-20,000=0

how and why does the 40,000 move to the left ?



Its just subtracting 40,000 from both sides.

Say for example x+5=y

You can say that (x+5)-5=(y)-5 right?

so then that means that x=y-5

After that I just factored out a 2 to make the simplification easier.


BTW, what the hell kind of college is this?