#1

Ive got this problem and i cant figure it out and its driving me crazy, can anyone help me out?

I found the frequency, and thought the speed would be 12/1.4, which comes to 8.57 m/s. so i thought f=speed/wavelength, so 8.57/5.4=1.58 Hz. what am i doing wrong?

I found the frequency, and thought the speed would be 12/1.4, which comes to 8.57 m/s. so i thought f=speed/wavelength, so 8.57/5.4=1.58 Hz. what am i doing wrong?

#2

i used to have to do that **** for astronomy, stupid online homework.

#3

Is frequency == wavelength/velocity instead?

#4

no velocity=frequency*wavelength

andd the period of a wave is the time taken for 1 wave to pass a point if that helps

andd the period of a wave is the time taken for 1 wave to pass a point if that helps

#5

Is frequency == wavelength/velocity instead?

F=W/V

F=5.4/8.57=0.63 Hz, INCORRECT

something is wrong with my velocity, but idk how to get it from this graph

#6

1.429 Hz ?

#7

get the velocity fromt eh graph, V=d/t

#8

1.429 Hz ?

thats it, thanks! what did i do wrong?

#9

1.429 Hz ?

yes

wave's period= 0.7 s

T=1/F (=) F=1/0.7 (=) F=1.429 Hz

#10

thats it, thanks! what did i do wrong?

Well, i calculated the period from the first graph: 1,3-0,6=0,7 s

frequency=1/period, so 1/0,7 is your answer.

Edit: beaten

*Last edited by BluBluBlu at Feb 5, 2009,*

#11

OH.

Why is the speed 12/1.4? If the wavelength is 5.4m, the super-rough speed would be (disgustingly) 5.4m/.7s. This is easier than I'm making it, I'm sure. That's 7.714 m/s (I think).

SHEdit: /pointless effort

Why is the speed 12/1.4? If the wavelength is 5.4m, the super-rough speed would be (disgustingly) 5.4m/.7s. This is easier than I'm making it, I'm sure. That's 7.714 m/s (I think).

SHEdit: /pointless effort

#12

umm.. if youre looking for the frequency my physics book says that f=1/T=

w= angular velocity

so i looked at the graph and guessed that time for one oscillation is about 0.7 seconds. so i put 1/.7 and got about 1.4286 rounded. i really have no idea if this is right we havent gone this far in my physics class. but i figured id guess and possibly help.

*w*/2piw= angular velocity

so i looked at the graph and guessed that time for one oscillation is about 0.7 seconds. so i put 1/.7 and got about 1.4286 rounded. i really have no idea if this is right we havent gone this far in my physics class. but i figured id guess and possibly help.

#13

actually looks like you already got the answer. nevermind then lol

#14

last question, anyone know how to get the amplitude other than just looking and guessin?