Ive got this problem and i cant figure it out and its driving me crazy, can anyone help me out?

I found the frequency, and thought the speed would be 12/1.4, which comes to 8.57 m/s. so i thought f=speed/wavelength, so 8.57/5.4=1.58 Hz. what am i doing wrong?
i used to have to do that **** for astronomy, stupid online homework.
Quote by Eminored
Hentai. It's a completely different world that will rip your eye-sockets and and skull-screw you with its tentacles.

[IN PHIL WE TRUST]

Quote by Trowzaa
I only play bots. Bots never abandon me. (´・ω・`)

no velocity=frequency*wavelength

andd the period of a wave is the time taken for 1 wave to pass a point if that helps
Quote by SteveHouse

F=W/V
F=5.4/8.57=0.63 Hz, INCORRECT
something is wrong with my velocity, but idk how to get it from this graph
1.429 Hz ?
Quote by Habit Zero
This dude wins for logic.

Logic is invisible, just like your new trophy Blu.
get the velocity fromt eh graph, V=d/t
Quote by BluBluBlu
1.429 Hz ?

thats it, thanks! what did i do wrong?
Quote by BluBluBlu
1.429 Hz ?

yes

wave's period= 0.7 s

T=1/F (=) F=1/0.7 (=) F=1.429 Hz
Quote by reelbigfish2020
thats it, thanks! what did i do wrong?

Well, i calculated the period from the first graph: 1,3-0,6=0,7 s

Edit: beaten
Quote by Habit Zero
This dude wins for logic.

Logic is invisible, just like your new trophy Blu.
Last edited by BluBluBlu at Feb 5, 2009,
OH.

Why is the speed 12/1.4? If the wavelength is 5.4m, the super-rough speed would be (disgustingly) 5.4m/.7s. This is easier than I'm making it, I'm sure. That's 7.714 m/s (I think).

SHEdit: /pointless effort

[IN PHIL WE TRUST]

Quote by Trowzaa
I only play bots. Bots never abandon me. (´・ω・`)

umm.. if youre looking for the frequency my physics book says that f=1/T=w/2pi
w= angular velocity
so i looked at the graph and guessed that time for one oscillation is about 0.7 seconds. so i put 1/.7 and got about 1.4286 rounded. i really have no idea if this is right we havent gone this far in my physics class. but i figured id guess and possibly help.