#1
Ok so im doing the pythagorean theorem and one of the hypotenuses i need to use has a radical in it (3 root 5). So my equation is 3 root 5 squared = 2 squared + 6 squared

What do i do about the number and the radical?? I know the squared sign cancels out the radical, but then do I multiply 3 and 5, then square them, or square them individually and add the results??
"Imagine all the people, sharing all the world"
-John Lennon
#3
three root five squared is the same as 3 times five!!!


is this for geometry???
cuz thats what i'm currently enrolled in...
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#4
yea I know thats the obvious thing, but I think my teacher wanted us to cancel out the radical or something


I dunno I could be thinking of some other thing she showed us....
"Imagine all the people, sharing all the world"
-John Lennon
#7
Why are people idiots these days?

EDIT: Hahaha you go to East, no wonder.
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#10
Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)
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#11
Quote by JahCohBee
Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)

Uh no.
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This man knows his beverages.
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^somebody get this man 30 million dollars.
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90.200.36.223 is my IP. Try me.
#12
I still don't get where the difficulty is in squaring it ...

Of course the equation doesn't make any sense anyway since 3 root 5 squared doesn't equal 2 squared + 6 squared ...

Quote by JahCohBee
Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)

That makes astronomically little sense.
Last edited by Malakian88 at Feb 19, 2009,
#13
My bad... I'm retarded... ****ing math... >_<
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#16
What are you trying to find, it seems like you already know all the sides, (3root5, 2 and 6) right? There's no point in doing the equation in the first place...
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