#1

Ok so im doing the pythagorean theorem and one of the hypotenuses i need to use has a radical in it (3 root 5). So my equation is 3 root 5 squared = 2 squared + 6 squared

What do i do about the number and the radical?? I know the squared sign cancels out the radical, but then do I multiply 3 and 5, then square them, or square them individually and add the results??

What do i do about the number and the radical?? I know the squared sign cancels out the radical, but then do I multiply 3 and 5, then square them, or square them individually and add the results??

#2

3 root 5 all squared? Multiply 3 root 5 by itself ... 3 x root 5 x 3 x root 5 ....

#3

three root five squared is the same as 3 times five!!!

is this for geometry???

cuz thats what i'm currently enrolled in...

is this for geometry???

cuz thats what i'm currently enrolled in...

#4

yea I know thats the obvious thing, but I think my teacher wanted us to cancel out the radical or something

I dunno I could be thinking of some other thing she showed us....

I dunno I could be thinking of some other thing she showed us....

#5

multiply everything by the square root of 5.

#6

kill your geometry teacher

its the only way

its the only way

#7

Why are people idiots these days?

EDIT: Hahaha you go to East, no wonder.

EDIT: Hahaha you go to East, no wonder.

#8

try multiplying all by 3root5. may help, if I get the time I'll do it and post here.

#9

(3 root 5)squared...

(3 squared x root 5 squared)

(9 x 5)

45

(3 squared x root 5 squared)

(9 x 5)

45

#10

Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)

#11

Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)

Uh no.

#12

I still don't get where the difficulty is in squaring it ...

Of course the equation doesn't make any sense anyway since 3 root 5 squared doesn't equal 2 squared + 6 squared ...

That makes astronomically little sense.

Of course the equation doesn't make any sense anyway since 3 root 5 squared doesn't equal 2 squared + 6 squared ...

Ok kids... You gotta cancel out the radical... take 3 root 5 then do ^5... root 5 and ^5 cancel eachother out... then your equation becomes: 3 = ((2^2)^5)+((6^2)^5)

That makes astronomically little sense.

*Last edited by Malakian88 at Feb 19, 2009,*

#13

My bad... I'm retarded... ****ing math... >_<

#14

more to the point, why did you post this on UG?

its not exactly a maths forum

its not exactly a maths forum

#15

(3 root 5)^2

=(3^2)(5)

=(3^2)(5)

#16

What are you trying to find, it seems like you already know all the sides, (3root5, 2 and 6) right? There's no point in doing the equation in the first place...