#1

On this problem, I need to simplify this:

(10x^3y^5)^-3

I've got this so far: 10x^-9y^-15.

How do I get rid of the negative exponents 9 and 15?

(10x^3y^5)^-3

I've got this so far: 10x^-9y^-15.

How do I get rid of the negative exponents 9 and 15?

#2

move em to the bottom. or up. whatever needs to happen. i do believe.

#3

Remember.. x^-1 = 1/x

So 10x^-9y^-15 is = 1/(10x^9y^15)

So 10x^-9y^-15 is = 1/(10x^9y^15)

#4

Why didn't you do anything to the 10x?

Edit: this problem doesn't make sense... How do you put an exponent on an exponent? Or does the "^" mean something else?

Edit: this problem doesn't make sense... How do you put an exponent on an exponent? Or does the "^" mean something else?

*Last edited by merfsullivan at Feb 25, 2009,*

#5

stick the neg exponents in the denomintaor

#6

it would be 10/(x^9y^15)

#7

No no no no. You are supposed to expand the exponents. Example -> (x-2)^3 = (x-3)(x-3)(x-3) and NOT (x^3-8)

#8

what does ^ mean?

#9

Exponent.

#10

Exponent.

What does exponent mean?

Like I'm good at maths but I don't know how you guys write it on here?

#11

If you don't know what an exponent is, then I seriously doubt your math skills.

#12

I might nkow what it is but not using that word

#13

Distribute the ^ -3 to the 10, x, and y. so you get 1/(10^3x^9y^15),like someone already showed the negative exponent can be taken as the reciprocal of any given exponent and the 10 is inside the quantity so it also gets raised to -3

*Last edited by rcbass at Feb 25, 2009,*

#14

In other words x^3 is x to the power of three/third degree/cubed.

EDIT: rcbass - that is wrong. Expand the terms, not just multiply out the exponents.

EDIT: rcbass - that is wrong. Expand the terms, not just multiply out the exponents.

#15

You have to raise the coefficients to ^-3, as well.

#16

Okay - I give up. This is what happens when you ask UG for math help.

#17

Okay - I give up. This is what happens when you ask UG for math help.

Well, rcbass is right, anyway.