#1

A 2 kg particle moves at a constant speed of 4.0 m/s around a circle of radius 5 m.

(c) What is the angular speed of the particle? (In radians / second)

How do you solve this problem correctly? I came out with two different answers: 5.027 and 43.35 and both were wrong. Can somebody explain how its done?

(c) What is the angular speed of the particle? (In radians / second)

How do you solve this problem correctly? I came out with two different answers: 5.027 and 43.35 and both were wrong. Can somebody explain how its done?

#2

#3

The trip around the whole circle is 2*pi radians.

So angular speed = (4m/s) / 2*pi*Radius / 2*pi

First 2 terms being the proportion of the circumference travelled in one second, and the 3rd term to change it into radians.

But the short answer is angular speed = v/R

= 4m/s / 5m

= 0.8 radians/s

So angular speed = (4m/s) / 2*pi*Radius / 2*pi

First 2 terms being the proportion of the circumference travelled in one second, and the 3rd term to change it into radians.

But the short answer is angular speed = v/R

= 4m/s / 5m

= 0.8 radians/s

#4

The trip around the whole circle is 2*pi radians.

So angular speed = (4m/s) / 2*pi*Radius / 2*pi

First 2 terms being the proportion of the circumference travelled in one second, and the 3rd term to change it into radians.

But the short answer is angular speed = v/R

= 4m/s / 5m

= 0.8 radians/s

Totally wrong..

#5

The trip around the whole circle is 2*pi radians.

So angular speed = (4m/s) / 2*pi*Radius / 2*pi

First 2 terms being the proportion of the circumference travelled in one second, and the 3rd term to change it into radians.

But the short answer is angular speed = v/R

= 4m/s / 5m

= 0.8 radians/s

Good job, that worked. I dont get why you divide by 2pi again though, cancelling out the 2pi in the circumference equation. I thought you would have to multiply it to get the number of revolutions in terms of radians.

#6

i agree