#1
im wondering if one of my cheap marshall cabs is wired wrong. a diagram would be really help full.
#2
Wire 8 > 8 parallel: (8+8)/2 = 4

Wire 8 > 8 parallel: (8+8)/2 = 4

Wire those two pairs in series: 4+4 = 8

There you go.
Everyone is entitled to an opinion.

Feel free to express yours so I can make an informed judgement about how stupid you are.
#3
Quote by bubb_tubbs
Wire 8 > 8 parallel: (8+8)/2 = 4

Wire 8 > 8 parallel: (8+8)/2 = 4

Wire those two pairs in series: 4+4 = 8

There you go.



(8+8) / 2 = 4


16 / 2 = 8


uh?
#4
I believe if you wire all 4 in parallel and you will have an 8 ohm cab.

8+8+8+8/4=8

I think thats how it would work? Correct me if I'm wrong.
#8
Quote by i_am_metalhead
I believe if you wire all 4 in parallel and you will have an 8 ohm cab.

8+8+8+8/4=8

I think thats how it would work? Correct me if I'm wrong.
No, if you put all 8 in parallel you'd get 2 ohms total.

Bubb Tubbs had it right, but his equations are just confusing.

When adding resistors in parallel...

1/Rtotal=1/R1+1/R2+...1/Rn

Other way you can do it is like in the diagram, wiring two pairs in series of 16 ohms and then wiring the two pairs in parallel for a total of 8 ohms.
#12
Typically, a few notches above will not hurt anything. too much and something called flyback voltage will occur and arc the windings in your amp's OT, it's what happens when you don't have a cab connected. But it actually takes quite a bit of impedance to cause that to happen and people make a bigger deal out of it than it really is (mismatching a step or so upwards I mean, not running a load at all WILL kill your amp very quickly)

You should still try to match though, typically mismatching upwards just doesn't sound very good.
Last edited by al112987 at Aug 12, 2009,