#1

0.999... = x

9.999... = 10x

10x - x = 9x

9.999... - 0.999... = 9

9x = 9

x = 1

0.999... = 1

9.999... = 10x

10x - x = 9x

9.999... - 0.999... = 9

9x = 9

x = 1

0.999... = 1

#2

cool math bro.

#3

Except 0.999.... times 10 would make the last digit 0

#4

makes sense to me....

#5

Cool searchbar, bro.

#6

Oh you mean that horrid argument that ruined this thread?

They are one in the same. Now go live your life.

They are one in the same. Now go live your life.

#7

Not this **** again...

#8

welcome to math for 15 year olds

#9

Except 0.999.... times 10 would make the last digit 0

the extra 0 is redundant. it has no influence what so ever on any facet of the equation so there is no purpose in including it

plus. its an infinite sting of 9's

*Last edited by Wylde14 at Aug 10, 2009,*

#10

omg no wai.

lyk srsly?

...

lyk srsly?

...

#11

0.999... = x

9.999... = 10x

10x - x = 9x

9.999... - 0.999... = 9

9x = 99x - 9 = 9 - 9

x = 0

0.999... = 0

???

EDIT: wait a sec, im a total idiot. man, this is what summer does to you

#12

i think i've seen this at least over 25 times here at UG.

#13

Yes, we know. There was a LOOOONGG thread on it, and those of it who can do maths and aren't imbeciles already accept this proof.

*reported*

*reported*

#14

emm. yeah, 0.9999... does = 1. Who cares?

#15

0.999... = x

9.999... = 10x10x - x = 9x

9.999... - 0.999... = 9

9x = 9

x = 1

0.999... = 1

cool when you substituted you didn't substitute on the right side. how awesome is that

#16

why would 9x equal 9... that's your error.

9 times 0.999... does not equal 9. if you're workin with aproximations then yes, 0.999... is aproximately 1

9 times 0.999... does not equal 9. if you're workin with aproximations then yes, 0.999... is aproximately 1

#17

Still, .999 can't =1 because 1=1

.999 isn't 1.

.999 isn't 1.

#18

you just can't deal with infinities like that - what you are saying is "assume the later digits are insignificant... do some basic maths... and look the later digits are insignificant!" what you actually have here is closer to a proof by contradiction that the statement cannot be true

#19

This changes nothing.

#20

No ****.

#21

the extra 0 is redundant. it has no influence what so ever on any facet of the equation so there is no purpose in including it

this, plus it's an irrational number if all you do is increase it 10x

#22

Still, .999 can't =1 because 1=1

.999 isn't 1.

0.999... = x

9.999... = 10x

10x - x = 9x

9.999... - 0.999... = 9

9x = 9

x = 1

0.999... = 1

oooh look at the beautiful colours

get it now?

#23

Oh you mean that horrid argument that ruined this thread?

They are one in the same. Now go live your life.

this.. because 0.999.. is so unbelievably close to 1, it is 1.

look at from the point of view of probabilities.. if the chance was 0.9999... or 1 the differences between those two probabilities are so unbelievably small that they are one and the same.

#24

Still, .999 can't =1 because 1=1

.999 isn't 1.

If that is true then there exists a number c such that

0.999999999...<c<1

'...' means an infinite amount of 9s here. So if you can find that number c, then 0.999...=/= 1

#25

0.999...=1. Don't even try to debate it.

ITT: People with no grasp of infinity.

ITT: People with no grasp of infinity.

#26

I worked this out when I was like 5, sure I am genius but c'mon...

#27

You can't put a number on infinity.

#28

0.999...=1. Don't even try to debate it.

ITT: People with no grasp of infinity.

LISTEN PEOPLE :O

if you don't i'll prove to you guys that 0 times infinity isn't always 0