#1

Its been five years since I've done any physics, but the time has come where I need to be able to solve simple problems like the one below, and I can't for the life of me remember how.

If you guys could hold my hand and guide me through the process of solving a problem such as the one below it would be much appreciated.

I can work out that aircraft x takes one hour to get to B, and that aircraft y takes 2 hours 24 mins, but after that I'm lost.

P.S. Is all the info required in the question? I feel a bit embarrassed that I can't even work that out...

If you guys could hold my hand and guide me through the process of solving a problem such as the one below it would be much appreciated.

**Q:**Two airports, A and B, are 600 miles apart, one aircraft (x) takes off from A, and heads towards B at 600 miles per hour, another (y) takes off from B and heads towards A at 250 miles per hour. What distance from A do they meet?I can work out that aircraft x takes one hour to get to B, and that aircraft y takes 2 hours 24 mins, but after that I'm lost.

P.S. Is all the info required in the question? I feel a bit embarrassed that I can't even work that out...

#2

Neither aircraft x or y takes off on time.

Passengers g and h sleep at airport a and b.

Passengers g and h sleep at airport a and b.

#3

Figure how long it takes the distance between them to reach zero.

IE, at the beginning the distance is 600mi, after thirty minutes it's something like a couple hundred miles..... Distance == (X's speed * time) - (Y's speed * time). All you have to do is solve for time, amirite?

IE, at the beginning the distance is 600mi, after thirty minutes it's something like a couple hundred miles..... Distance == (X's speed * time) - (Y's speed * time). All you have to do is solve for time, amirite?

#4

you have to rest T-a to total time ant then you could figure where they meet... i think :S

#5

423.5

together they should cover 600 miles to meet

S = V*t

so

600*t + 250*t = 600

850*t = 600

t = 60/85

distance from A = distance that first plane covers = 60/85 * 600 = 423.529411

together they should cover 600 miles to meet

S = V*t

so

600*t + 250*t = 600

850*t = 600

t = 60/85

distance from A = distance that first plane covers = 60/85 * 600 = 423.529411

*Last edited by Regensgeliebte at Aug 12, 2009,*

#6

They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.

#7

They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.

Too bad that didn't work the other day over the Hudson.

#8

Neither aircraft x or y takes off on time.

Passengers g and h sleep at airport a and b.

I nearly spit out the orange juice in my mouth reading this.

#9

Too bad that didn't work the other day over the Hudson.

Which is why math equations are solved on paper, not in the sky.

#10

*reported for move to maths/science thread*

go there and ye shall be answered

go there and ye shall be answered

#11

They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.

this.

#12

make the airplanes into a function of distance with respect to time i.e

aircraft x would be d = 600t (d = distance, t= time)

aircraft y would be d = -250t + 600 (it's negative 250 because it's going in the opposite direction, and the +600 is because it is starting 600 miles away)

set the two d's equal to eachother

-250t + 600 = 600t

add 250t to both sides

600 = 850t

divide 850 from both sides and it will leave you with a time in hours

That should be the correct answer and method

aircraft x would be d = 600t (d = distance, t= time)

aircraft y would be d = -250t + 600 (it's negative 250 because it's going in the opposite direction, and the +600 is because it is starting 600 miles away)

set the two d's equal to eachother

-250t + 600 = 600t

add 250t to both sides

600 = 850t

divide 850 from both sides and it will leave you with a time in hours

That should be the correct answer and method

#13

**time of A flight = time of B flight**(obviously, because they both take off at the same time) (flight meaning time from take off to the "meeting")

once you got that figured out you can go with

**(distance from A) / time = speed of A (600)**

(distance form B) / time = speed of B (250)

(distance form B) / time = speed of B (250)

we get

**(distance from A) / speed of A (600) = time**

(distance form B) / speed of B (250) = time)

(distance form B) / speed of B (250) = time)

we put them together

**(distance from A) / speed of A (600) = (distance form B) / speed of B (250)**

and another one

**(distance fomr A) + (distance form B) = 600**

now i think you just put the equasions together and figure it out..

i'm not sure, because it's been a while since i've done phisics myself but i love it.

Best Regards, Serjem

#14

13

#15

Thank you folks, thats helped.

#16

Yeah and my goat can't ride in the same airplane as the wolf because the wolf will eat the goat!