# Basic physics help! Speed, distance time stuff.

Its been five years since I've done any physics, but the time has come where I need to be able to solve simple problems like the one below, and I can't for the life of me remember how.

If you guys could hold my hand and guide me through the process of solving a problem such as the one below it would be much appreciated.

Q: Two airports, A and B, are 600 miles apart, one aircraft (x) takes off from A, and heads towards B at 600 miles per hour, another (y) takes off from B and heads towards A at 250 miles per hour. What distance from A do they meet?

I can work out that aircraft x takes one hour to get to B, and that aircraft y takes 2 hours 24 mins, but after that I'm lost.

P.S. Is all the info required in the question? I feel a bit embarrassed that I can't even work that out...
...Bleep Bloop...
Neither aircraft x or y takes off on time.

Passengers g and h sleep at airport a and b.
My Musical attempts

Quote by TOMMYB22
Dammit, beaten to it, and by someone with the same name

CURSE YOU TOMMYT!!!!!!!!!!!!

Quote by daeqwon10000
I hate tommyt and the high horse which he rides upon
Figure how long it takes the distance between them to reach zero.

IE, at the beginning the distance is 600mi, after thirty minutes it's something like a couple hundred miles..... Distance == (X's speed * time) - (Y's speed * time). All you have to do is solve for time, amirite?

[IN PHIL WE TRUST]

Quote by Trowzaa
I only play bots. Bots never abandon me. (´・ω・`)

you have to rest T-a to total time ant then you could figure where they meet... i think :S
TH3 G3Ar
- JCM 900 SL-X and SV MKII 100HD with LIne 6 sv412
-Bunch of pedals ( WD,BM,NR-2...)
-Ibanez Universe uv777pbk,Rg 2550&321mh
-http://backtorlyeh.bandcamp.com/
423.5

together they should cover 600 miles to meet
S = V*t
so
600*t + 250*t = 600
850*t = 600
t = 60/85

distance from A = distance that first plane covers = 60/85 * 600 = 423.529411
Originally Posted by Twist of fate
I thought the "clean" button was to clean out the inside of the amp automatically, so I never pressed it.

Originally Posted by DjBrandenburg
pedals are stupid
Last edited by Regensgeliebte at Aug 12, 2009,
They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.
Quote by MightyAl
They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.

Too bad that didn't work the other day over the Hudson.

[IN PHIL WE TRUST]

Quote by Trowzaa
I only play bots. Bots never abandon me. (´・ω・`)

Quote by tommyt
Neither aircraft x or y takes off on time.

Passengers g and h sleep at airport a and b.

I nearly spit out the orange juice in my mouth reading this.
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
Quote by SteveHouse
Too bad that didn't work the other day over the Hudson.

Which is why math equations are solved on paper, not in the sky.
+Infinity

Listen to ExtremeMetalFTW, he knows what he is talking about...

Quote by vmanoman
I clicked System Restore and it said "System Restore Is Unable To Protect You".

^^SO KVLT!!
*reported for move to maths/science thread*

go there and ye shall be answered
The only 6 words that can make you a better guitarist:

Learn theory
Practice better
Practice more
Quote by MightyAl
They don't meet. Air traffic control exists to prevent aircraft meeting in-flight.

this.
Quote by Demonikk
'Practice amp' = amp you practice with? In my case, Peavey 6505+ and 4x12
I don't do things small

Except children.
make the airplanes into a function of distance with respect to time i.e

aircraft x would be d = 600t (d = distance, t= time)
aircraft y would be d = -250t + 600 (it's negative 250 because it's going in the opposite direction, and the +600 is because it is starting 600 miles away)

set the two d's equal to eachother

-250t + 600 = 600t

600 = 850t

divide 850 from both sides and it will leave you with a time in hours

That should be the correct answer and method
time of A flight = time of B flight (obviously, because they both take off at the same time) (flight meaning time from take off to the "meeting")

once you got that figured out you can go with
(distance from A) / time = speed of A (600)
(distance form B) / time = speed of B (250)

we get
(distance from A) / speed of A (600) = time
(distance form B) / speed of B (250) = time)

we put them together

(distance from A) / speed of A (600) = (distance form B) / speed of B (250)

and another one
(distance fomr A) + (distance form B) = 600

now i think you just put the equasions together and figure it out..

i'm not sure, because it's been a while since i've done phisics myself but i love it.

Best Regards, Serjem
Quote by Moggan13
Serjem is like a Bishops testicals: Swollen
ಠ_ಠ
IIIIfb * KARKOLI * ytIIII(mostly rock... a little funky, a little hard just the way you want it )
Thank you folks, thats helped.
...Bleep Bloop...
Yeah and my goat can't ride in the same airplane as the wolf because the wolf will eat the goat!
████████████████████████████
███████████████████████████
█████████████████████████
██████████████████████████
███████████████████████████
███████████████████████████
███████████████████████████
███████████████████████████