#1
find the point(s) of intersection of y=-x^2 +5x+8 and y=2x-10

Help me out, pit. I've been working on this question forever and can't figure this out.

EDIT: Can you actually do the question, and lay out the steps for me? thanks. <3.
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Last edited by tsoyguitar at Sep 30, 2009,
#2
put 2x-10 in wherever the x appears in the other equation.
Solve for y, and then plug y into either equation and solve for x.
#3
y=y
-x^2 +5x + 8 =2x -10
-x^2 +3x+18=0
(-x-3)(x-6)
x=-3 x=6
Use the maths thread from now on though please.

EDIT: then ofcourse sub in the X values to your original y=
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#5
just put into a graphing calculator and do 2nd trace, intersect..
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#6
You could make them equal too each other and then solve for x?
Then substitute that into of one of the equations to get the y value and then get your co-ordinates.
I'm currently studying for a vector functions test, so graphical algebra isn't in my my mind right now lol

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#7
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EDIT: Can you actually do the question, and lay out the steps for me? thanks. <3.

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#8
y=-x^2 +5x+8 and y=2x-10

You can substitute "2x-10" for "y" because they are equal. So 2x-10=x^2 +5x+8. Solve that and you will find x. Plug the number into one of the other equations and find y.
#9
Quote by Masonpwiley
y=-x^2 +5x+8 and y=2x-10

You can substitute "2x-10" for "y" because they are equal. So 2x-10=x^2 +5x+8. Solve that and you will find x. Plug the number into one of the other equations and find y.

I said that like 10 minutes ago and did the steps for him but I don't even get thanks for these kinda things
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#10
This is the latest thread I could find...

if x+y=7 and x^2-y^2=21 find the value of 2x+3y.

please :[