find the point(s) of intersection of y=-x^2 +5x+8 and y=2x-10

Help me out, pit. I've been working on this question forever and can't figure this out.

EDIT: Can you actually do the question, and lay out the steps for me? thanks. <3.
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Last edited by tsoyguitar at Sep 30, 2009,
put 2x-10 in wherever the x appears in the other equation.
Solve for y, and then plug y into either equation and solve for x.
y=y
-x^2 +5x + 8 =2x -10
-x^2 +3x+18=0
(-x-3)(x-6)
x=-3 x=6

EDIT: then ofcourse sub in the X values to your original y=
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Last edited by Venice King at Sep 30, 2009,
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just put into a graphing calculator and do 2nd trace, intersect..
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You could make them equal too each other and then solve for x?
Then substitute that into of one of the equations to get the y value and then get your co-ordinates.
I'm currently studying for a vector functions test, so graphical algebra isn't in my my mind right now lol

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Last edited by Aussie_Warrior at Sep 30, 2009,
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EDIT: Can you actually do the question, and lay out the steps for me? thanks. <3.

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y=-x^2 +5x+8 and y=2x-10

You can substitute "2x-10" for "y" because they are equal. So 2x-10=x^2 +5x+8. Solve that and you will find x. Plug the number into one of the other equations and find y.
Quote by Masonpwiley
y=-x^2 +5x+8 and y=2x-10

You can substitute "2x-10" for "y" because they are equal. So 2x-10=x^2 +5x+8. Solve that and you will find x. Plug the number into one of the other equations and find y.

I said that like 10 minutes ago and did the steps for him but I don't even get thanks for these kinda things
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This is the latest thread I could find...

if x+y=7 and x^2-y^2=21 find the value of 2x+3y.