#1
I've been trying to get this one for awhile but am completely vexed. Using the elimination method.

9x-5y=1
-18x+10y=1


I mean whenever I multiply 5 and 2, to solve for x, everything ends up canceling out.

Help would be much appreciated.

#2
y = (1-9x)/5

-18x + 10[(1-9x)/5] = 1
-18x + 2(1-9x) = 1
-18x + 2 - 18x = 1
-36x = -1
x = 1/36

amidoinitright?

EDIT: shit, no i'm not... yeah, should be

y = -(1-9x)/5

yeah in that case x would cancel out... i guess there just is no x in that, but... i dont like math sooo...

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Last edited by SPBY at Oct 27, 2009,
#3
Its linearally dependent. You have a free variable.
9x-5y=1
9x=5y+1
x=5/9y+1/9
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#4
these two systems of eqns have no solution. Basically if you picture these equations as lines in a 2d coordinate system, they never intersect. If you plot the two lines, you should see no intersection.
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#5
Quote by angusyoung101
these two systems of eqns have no solution. Basically if you picture these equations as lines in a 2d coordinate system, they never intersect. If you plot the two lines, you should see no intersection.

+1

If you solve each equation for y, then set the two equal to each other, you get the statement 1 = -2. Obviously, this is not true, therefore there is no intersection.
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