#1

guys i'm stuck on a maths problem on differentiation :/ there's a quintic graph with the equation y=x^5 - x^3. i have to find the coordinates of the point P where the curve crosses the positive x axis. So this must mean y=0. But can i do x^5 - x^3 and end up with x^2. I don't think i can. because that would mean x=0 which it clearly does not. After finding the coordinates (x,0) how would i go about finding the equation of the tangent and normal to P.

Also for the equation f(x)=x^3-3x^2+4x+1 of which f'(x)= 3x^2-6x+4. how would i find all the values of x for which the curve has a gradient of 13??

any help much appreciated.

Also for the equation f(x)=x^3-3x^2+4x+1 of which f'(x)= 3x^2-6x+4. how would i find all the values of x for which the curve has a gradient of 13??

any help much appreciated.

#2

The answer is 42. Trust me.

#3

The answer is 42. Trust me.

but what's the question :P

#4

^i don't know - i checked the math/science question thread and couldn't find it

*reported*

*reported*

#5

why ask the pit this question?