#1
Hey guys, I'm having some trouble with this here question:

If X is the continued square root of 2 (shown in image attachment), find X algebraically. It gives a hint saying "Find X^2 in terms of X". I'm not sure what to do here, anyone up for helping?

Thanks ^_^
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#3
It's i.
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#4
I gonna gonna have to go with 2.


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#8
Actually, X is 2. I need to show how to figure that out using algebra though :P. Thanks any way
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#10
Quote by GezzyDiversion
surely X^2 is just 2+2+2+2+2+2..................


I would have thought x^2 would have been 2+r2+rr2+rrr2... because it's a root of a root of a root etc so you just go up 1 root each time.
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#11
Quote by GezzyDiversion
surely X^2 is just 2+2+2+2+2+2..................


Squaring X only gets rid of the first surd though D:
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#12
square both sides

x^2 = 2 + x
xsqu - x - 2 = 0

quadratic equation


Oh shit, I just won all over the place
Last edited by Declan87 at Jun 28, 2010,
#13
x^2 = 2 + x?
:. x^2 - x - 2 = 0
x= -2 or 1
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#16
Thanks guys :P
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#17
The square route of two is the same as 2 to the power of a half. That will help you show it algebraically.
#18
Quote by untalented
x^2 = 2 + x?
:. x^2 - x - 2 = 0
x= -2 or 1


wrong way round.
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#19
Quote by Sol9989
wrong way round.

yeah, i realised after
to be fair, i have a headache
Quote by Meths

I don't think any words should be censored.

Especially faggot since homos aren't real people and all.

Quote by sam b
Man City wont win anything and finish below Arsenal.

city: 3rd + FA cup winners.
arsenal: 4th
#20
x = 2^1/2 and so on

x^2 = 2 + 2^1/2 and so on

x^2 = 2 + x

x^2 - x - 2 = 0

(x - 2)(x + 1) = 0

x = 2 or -1
Last edited by br33dlove at Jun 28, 2010,