#1
Two rectangular tiles each of 1 ft sides overlap each other such that the overlapping region is a regular octagon. What is the area of the overlapping region?

please help
#3
if they have 1 foot sides... they aren't rectangles. We need both dimensions.
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#5
Quote by MakinLattes



That's a square, a rectangular is not always a square. But if that's that... I'd say 1-2/9 ft.
Last edited by Zeletros at Sep 18, 2010,
#6
all squares are rectangles.

that's like saying an equilateral triangle isn't a triangle.

the way the question was stated implied that all sides of the rectangles were equal.

edit:

Last edited by MakinLattes at Sep 18, 2010,
#7
Quote by MakinLattes
all squares are rectangles.

that's like saying an equilateral triangle isn't a triangle.



All SQUARES are rectangles.

but not ALL RECTANGLES are squares.
#8
dammit ok just pretend i said squares instead if it will help. squares are rectangles you know. please help me out tho haha i have no idea how to do this
#9
Quote by Zeletros
All SQUARES are rectangles.

but not ALL RECTANGLES are squares.

I made them more traditionally rectangular.

and, what do you know, there's an irregular octagon.
#12
Zeletros is correct, but here's your working:

Length of a side of your octagon is x

Length of a side of one of the triangles outside of the octagon is x/rt.2

Length of a side of a square is 1ft.

Therefore 1ft = 3x/rt.2

multiply by rt.2 and you get rt.2 = 3x

divide by 3 and you get x = rt.2/3

That's the length of the side of your octagon


Area of an octagon is S^2 - x^2 where S is the length of your square.

1^2 - (rt.2/3)^2 = 7/9

so the octagon has an area of 7/9ft^2
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#13
Quote by instagata0
Zeletros is correct, but here's your working:

Length of a side of your octagon is x

Length of a side of one of the triangles outside of the octagon is x/rt.2

Length of a side of a square is 1ft.

Therefore 1ft = 3x/rt.2

multiply by rt.2 and you get rt.2 = 3x

divide by 3 and you get x = rt.2/3

That's the length of the side of your octagon


Area of an octagon is S^2 - x^2 where S is the length of your square.

1^2 - (rt.2/3)^2 = 7/9

so the octagon has an area of 7/9ft^2



I forgot the ^2.
#14
Totally thought this said meth problem...
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