#1

Two rectangular tiles each of 1 ft sides overlap each other such that the overlapping region is a regular octagon. What is the area of the overlapping region?

please help

please help

#2

Show me a picture of two rectangular tiles forming an octagon.

#3

if they have 1 foot sides... they aren't rectangles. We need both dimensions.

#4

#5

That's a square, a rectangular is not always a square. But if that's that... I'd say 1-2/9 ft.

*Last edited by Zeletros at Sep 18, 2010,*

#6

all squares are rectangles.

that's like saying an equilateral triangle isn't a triangle.

the way the question was stated implied that all sides of the rectangles were equal.

edit:

that's like saying an equilateral triangle isn't a triangle.

the way the question was stated implied that all sides of the rectangles were equal.

edit:

*Last edited by MakinLattes at Sep 18, 2010,*

#7

all squares are rectangles.

that's like saying an equilateral triangle isn't a triangle.

All SQUARES are rectangles.

but not ALL RECTANGLES are squares.

#8

dammit ok just pretend i said squares instead if it will help. squares are rectangles you know. please help me out tho haha i have no idea how to do this

#9

All SQUARES are rectangles.

but not ALL RECTANGLES are squares.

I made them more traditionally rectangular.

and, what do you know, there's an irregular octagon.

#10

7/9 ft, I already said that

#11

thats wrong. the answers are in the back of the book its supposed to be 119.29insquared

#12

Zeletros is correct, but here's your working:

Length of a side of your octagon is x

Length of a side of one of the triangles outside of the octagon is x/rt.2

Length of a side of a square is 1ft.

Therefore 1ft = 3x/rt.2

multiply by rt.2 and you get rt.2 = 3x

divide by 3 and you get x = rt.2/3

That's the length of the side of your octagon

Area of an octagon is S^2 - x^2 where S is the length of your square.

1^2 - (rt.2/3)^2 = 7/9

so the octagon has an area of 7/9ft^2

Length of a side of your octagon is x

Length of a side of one of the triangles outside of the octagon is x/rt.2

Length of a side of a square is 1ft.

Therefore 1ft = 3x/rt.2

multiply by rt.2 and you get rt.2 = 3x

divide by 3 and you get x = rt.2/3

That's the length of the side of your octagon

Area of an octagon is S^2 - x^2 where S is the length of your square.

1^2 - (rt.2/3)^2 = 7/9

so the octagon has an area of 7/9ft^2

#13

Zeletros is correct, but here's your working:

Length of a side of your octagon is x

Length of a side of one of the triangles outside of the octagon is x/rt.2

Length of a side of a square is 1ft.

Therefore 1ft = 3x/rt.2

multiply by rt.2 and you get rt.2 = 3x

divide by 3 and you get x = rt.2/3

That's the length of the side of your octagon

Area of an octagon is S^2 - x^2 where S is the length of your square.

1^2 - (rt.2/3)^2 = 7/9

so the octagon has an area of 7/9ft^2

I forgot the ^2.

#14

Totally thought this said meth problem...

laters

laters