#1
Anyone knows how to prove that

d(U*V) = UdV + VdU


I know how to prove that (U*V)'= U'V + V'U,
and I'm not sure if it's the same thing.


If you have no idea what I'm talking about, here is a kitten:





He looks confused, just like you!
Last edited by Zeletros at Dec 11, 2011,
#2
you mean how f(x) * g(x) differentiated is
f'(x)*g(x) + f(x) * g'(x) ?


No clue.
#5
Don't remember a damn thing about math, but...my god, that kitten is adorable.
#7
Quote by nigeltheginger
http://en.wikipedia.org/wiki/Product_rule ?

I know how to do the maths but I'm not entirely sure how you'd prove it, though there are some proofs on there

Also, that second one looks to be the same, just sometimes differentials are presented as dy/dx and sometimes as f'(x)



I think that will do it. Just need to make the teacher believe I have any idea what I'm writing about..


Yeah, this will work nicely, though I still have no idea what's going on there, I'm great at practice math, know nothing about theory...


Just like in music
Last edited by Zeletros at Dec 11, 2011,
#8
Good that you found what you were looking for but seriously, there's a Maths help thread.
#9
Quote by Zeletros





He looks confused, just like you!


This will start a RIOT! in me
#10
The second equation is exactly the same as the first, the prime (') just means differential and is mainly used in higher order mathematics and physics where there are too many letters to handle (thats where I used it anyway).
#13
Quote by cornmancer
Hooray for Algebra II and not understanding any of that!



It's Algebra I, I'm only on 1st semester


I understand math... meaning, I mostly know all the answers or how to get to them during practices, but theory...