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Jose is traveling to paris. Kayla left 2.1 hours later and traveled 35mi/hr faster. After 1.2 hours, kayla caught up. Find jose`s average speed

k hurry
average 76.3 miles per hour
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Not fast enough to beat Kayla to Paris
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I'm sorry but you must specify with whom Kayla caught up? I assume she is traveling to Paris as well but it is not stated. Also does the .1 specify 10 minutes or 6 minutes (a valid question based on the common nomenclature of time)?

Assuming you mean 2 Hours 6 minutes and Kayla's average speed is 100mi/hr then jose is traveling 65mi/hr
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Last edited by Drmckool at Apr 25, 2013,
Jose's average is 20 mph.

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More than 12 parsecs.
.5 past light speed
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Ludicrous speed.
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btw its 20 duh
Because they're not in Paris yet, duh.
ok here is how.
dist. traveled by Kayla = 35*1.2 = 42 miles = dist. traveled by Jose
time spent traveling by Jose = 2.1 h
average speed of Jose = 42 miles / 2.1 hours = 20 miles/hour
Last edited by rageahol at Apr 25, 2013,
His average speed is go to hell or start using SI units. And don't use decimals for time except to indicate fractions of a second.
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That's one racist math problem.

Making the Mexican the slow one.
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Quote by rageahol
ok here is how.
dist. traveled by Kayla = 35*1.2 = 42 miles = dist. traveled by Jose
time spent traveling by Jose = 2.1 h
average speed of Jose = 42 miles / 2.1 hours = 20 miles/hour

Your answer is correct, but your working of the problem is wrong. It doesn't say Kayla is going 35 miles/hr, it says she's moving 35 miles/hr faster

So it's

K's speed = x + 35
J's speed = x

If they caught up 1.2 hours after the initial delay of 2.1 hours, it means at the moment they caught up, Jose had been traveling 3.3 hours. All that being said:

3.3x = 1.2(35+x)
3.3x = 42 + 1.2x
2.1x = 42
x = 20
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My initial thought too. He's either in remedial math or is just crying for attention.
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Anyway I have technically statutory raped #nice

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Shit and I just had a test in this crap
math is hard
pinga
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Jose is obviously riding in the back of a packed produce truck with a bunch of 'cousins', Those things dont go much faster that 50mph.

I'll say 42 mph.
Jose is still mowing my lawn at 35mi/hr.
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I waited for the rape.

...

...but the rape never came
You think algebra is hard? Chump.

Somebody get this guy some Calculus. Then, shove some Experimental Math his way.
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More than 12 parsecs.

I'm hoping (based on your name) that this is tongue-in-cheek. We all know by now that a parsec is a measurement of distance. Right?

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Shit son. Kayla caught up that quickly? Jose is a little bitch.

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Shit son. Kayla caught up that quickly? Jose is a little bitch.

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She's going 20mph. I actually miss doing these simple little problems.
*55 mph
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Anyway I have technically statutory raped #nice

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once a girl and i promised to never leave each other

since that promise was broken

i dont make promises any more
Guys I solved this like 100 years ago please stop
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That's one racist math problem.

Making the Mexican the slow one.

Because he has to stop at every street corner and sell some oranges to finance his trip to paris.

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Anyway I have technically statutory raped #nice

Quote by EndThecRinge51
once a girl and i promised to never leave each other

since that promise was broken

i dont make promises any more