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#1
Jose is traveling to paris. Kayla left 2.1 hours later and traveled 35mi/hr faster. After 1.2 hours, kayla caught up. Find jose`s average speed

k hurry
#2
average 76.3 miles per hour
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#3
Do your own homework
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#5
I'm sorry but you must specify with whom Kayla caught up? I assume she is traveling to Paris as well but it is not stated. Also does the .1 specify 10 minutes or 6 minutes (a valid question based on the common nomenclature of time)?

Assuming you mean 2 Hours 6 minutes and Kayla's average speed is 100mi/hr then jose is traveling 65mi/hr
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Last edited by Drmckool at Apr 25, 2013,
#6
Jose's average is 20 mph.

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#9
This is why we can't have nice things, assholes.
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#11
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Don't you have a formula sheet full of kinematic equations? Let me guess, "I used it to roll up a fat spliff". Sigh

shit what else is paper good for

btw its 20 duh
#14
the answer is 20
ok here is how.
dist. traveled by Kayla = 35*1.2 = 42 miles = dist. traveled by Jose
time spent traveling by Jose = 2.1 h
average speed of Jose = 42 miles / 2.1 hours = 20 miles/hour
Last edited by rageahol at Apr 25, 2013,
#16
His average speed is go to hell or start using SI units. And don't use decimals for time except to indicate fractions of a second.
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#20
That's one racist math problem.

Making the Mexican the slow one.
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#21
Quote by rageahol
the answer is 20
ok here is how.
dist. traveled by Kayla = 35*1.2 = 42 miles = dist. traveled by Jose
time spent traveling by Jose = 2.1 h
average speed of Jose = 42 miles / 2.1 hours = 20 miles/hour


Your answer is correct, but your working of the problem is wrong. It doesn't say Kayla is going 35 miles/hr, it says she's moving 35 miles/hr faster

So it's

K's speed = x + 35
J's speed = x

If they caught up 1.2 hours after the initial delay of 2.1 hours, it means at the moment they caught up, Jose had been traveling 3.3 hours. All that being said:

3.3x = 1.2(35+x)
3.3x = 42 + 1.2x
2.1x = 42
x = 20
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#23
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Wait you're in grade 9?


My initial thought too. He's either in remedial math or is just crying for attention.
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#26
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#27
Jose is obviously riding in the back of a packed produce truck with a bunch of 'cousins', Those things dont go much faster that 50mph.

I'll say 42 mph.
#30
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math is hard

You think algebra is hard? Chump.
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I waited for the rape.

...


...but the rape never came
#31
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You think algebra is hard? Chump.

Somebody get this guy some Calculus. Then, shove some Experimental Math his way.
#32
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More than 12 parsecs.


I'm hoping (based on your name) that this is tongue-in-cheek. We all know by now that a parsec is a measurement of distance. Right?

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#34
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Shit son. Kayla caught up that quickly? Jose is a little bitch.


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#35
Quote by jetfuel495
Shit son. Kayla caught up that quickly? Jose is a little bitch.

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#37
*55 mph
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Anyway I have technically statutory raped #nice

Quote by EndThecRinge51
once a girl and i promised to never leave each other

since that promise was broken

i dont make promises any more
#39
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That's one racist math problem.

Making the Mexican the slow one.


Because he has to stop at every street corner and sell some oranges to finance his trip to paris.
#40
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Guys I solved this like 100 years ago please stop


You never admitted to being a ******, this thread just cannot end until you do.
Quote by EndTheRapture51
Anyway I have technically statutory raped #nice

Quote by EndThecRinge51
once a girl and i promised to never leave each other

since that promise was broken

i dont make promises any more
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