#1
i'm finding the concentration of OCl- by titration. I diluted 50ml of 0.2molL-1 S2O3 with 200ml H20 in a 250ml volumetric flask. So the concentration of the diluted S2O3 is:
(m1)*(v1)=(m2)*(v2)
0.2*0.05=(m1)*0.25 (volume is in litres)
(m1)= 0.04molL-1 S2O3
the volume of S2O3 in the titration is 0.02428L
moles of S2O3: n=cv
n=0.04*0.02428
n=9.712*(10^-4)mol

mole ratio of S2O3:OCl is 2:1
Therefore mo. of moles of OCl:
(9.712*(10^-4))/2=4.856*(10^-4)mol
volume OCl: 0.02L
concentration of OCl:
c=n/v
c=(4.856*(10^-4))/0.02
c=0.02428molL-1

However, I also diluted the OCl by adding 20ml OCl to 230ml H2O in a 250ml volumetric flask.
(m1)*(v1)=(m2)*(v2)
(m1)*0.02=0.02428*0.25
(m1)=(0.02428*0.25)/0.02
(m1)=0.3035molL-1
Therefore the concentration of OCl is 0.3035molL-1
#2
is this real life?
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#5
holy bajezus kid, those are some complex letters n numbers you be slinging my way. i think theres a math thread somewhere around here.
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#9
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#10
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Last edited by RealUnrealRob at Jun 29, 2013,
#20
Oh man. I'm a molecular biology student, so basic chemistry is second nature to me, but I'm fairly drunk right now. Just a second.
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#24
Yes, that seems right. I don't have a calculator so I didn't check all the math, but you're method is sound. I assume you know how to punch numbers into a calculator.
-The Crimson Fucker, aka PonyFan #376121
#27
umm...

correct.
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#28
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Yes, that seems right. I don't have a calculator so I didn't check all the math, but you're method is sound. I assume you know how to punch numbers into a calculator.

Oh! Thanks so much mate, really appreciate it.
#31
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#33
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#34
check your own goddamn work. i checked it and it's right but still man, damn
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#35
The method's right and the numbers look fine, but I can't be bothered looking for a calculator to check.
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