my math homework blows, i've got it all done except two problems any hel anyone can offer would be greatly appreciated here they are:

1) (x+1)(2x-3) = x+2 this one's answer should be in radical form

2) 3/x-2 + 4/x = 1

find the values of x
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ha ha u have math homework on the weekend. thats too bad. u know what rip dat shit up u aint ever gone use that later in life
1:
2x{2}+2x-3x-3=0
2x(x+1)-3(x+1)=0
(2x-3)(x+1)=0
x=3/2 or x=-1

for 2 is it:
3/(x-2)

or

(3/x)-2
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2x squared + 3x + 2x + 3x = x + 2
2x squared + 7x= 2

2, I don't have the symbols for on my computer

EDIT: Someone got to it before me. XD That always happens
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For number one expand bracket:-

2x^2 + 2x -3x -3 = x + 2

2x^2 - 2x - 5 = 0

For number two, multiply everyone by x(x-2) so it is:-

3x + 4(x-2) = x(x-2)

3x + 4x - 8 = X^2 - 2x

7x + 8 = x^2 - 2x

x^2 - 9x - 8 = 0

For both use the quadratic equation. Have fun
thanks
Quote by Prophet of Page
If Hendrix, Clapton and Page were to jam, the most impressive guitarist playing would be Paul Gilbert.

Member of the "Marty Friedman > You" Club. PM apocalypse13 or altronataku to join

member of the Mitch Hedberg pwns club pm Knives490 to join
Last edited by eviledge87 at Jan 6, 2007,
3/(x-2) + 4/x = 1x
3x/(x-2) +4=1x
3x+4(x-2)=1x(x-2)
3x+4x-8=x^2-2x
-x^2+9x-8=0
x^2-9x+8=0

blah blah blah
I'm so unique I don't even have a sig.