#1
my math homework blows, i've got it all done except two problems any hel anyone can offer would be greatly appreciated here they are:

1) (x+1)(2x-3) = x+2 this one's answer should be in radical form

2) 3/x-2 + 4/x = 1

find the values of x
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#2
ha ha u have math homework on the weekend. thats too bad. u know what rip dat shit up u aint ever gone use that later in life
#3
1:
2x{2}+2x-3x-3=0
2x(x+1)-3(x+1)=0
(2x-3)(x+1)=0
x=3/2 or x=-1

for 2 is it:
3/(x-2)

or

(3/x)-2
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#4
1 do the radicals yourself:

2x squared + 3x + 2x + 3x = x + 2
2x squared + 7x= 2

2, I don't have the symbols for on my computer

EDIT: Someone got to it before me. XD That always happens
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#5
Defy: LOL, i usualy get beat too so i rush it, and then when i post it i check for mistakes
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#6
For number one expand bracket:-

2x^2 + 2x -3x -3 = x + 2

2x^2 - 2x - 5 = 0

For number two, multiply everyone by x(x-2) so it is:-

3x + 4(x-2) = x(x-2)

3x + 4x - 8 = X^2 - 2x

7x + 8 = x^2 - 2x

x^2 - 9x - 8 = 0

For both use the quadratic equation. Have fun
#7
thanks
Quote by Prophet of Page
If Hendrix, Clapton and Page were to jam, the most impressive guitarist playing would be Paul Gilbert.


Member of the "Marty Friedman > You" Club. PM apocalypse13 or altronataku to join

member of the Mitch Hedberg pwns club pm Knives490 to join
Last edited by eviledge87 at Jan 6, 2007,
#8
3/(x-2) + 4/x = 1x
3x/(x-2) +4=1x
3x+4(x-2)=1x(x-2)
3x+4x-8=x^2-2x
-x^2+9x-8=0
x^2-9x+8=0

blah blah blah
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