#1

When you have a number divided by something divided by something divided by something, how do you do it? I have to simplify

(x+3)(x-1)

--------------

(x+2)(x-2)

-------------

(x+6)(x+1)

-------------

(x+2)

Please help!

(x+3)(x-1)

--------------

(x+2)(x-2)

-------------

(x+6)(x+1)

-------------

(x+2)

Please help!

#2

(x2+2x-3)/(x2-4)

---------------------

(x2+7x+6)/(x+2)

i think ....

[x2 being x squared]

---------------------

(x2+7x+6)/(x+2)

i think ....

[x2 being x squared]

#3

(x+6)(x+1)=x^2+7x+6 if that helps. I'm only in Algebra 2.

#4

no .. wait ....

#5

In a situation like this, multiply by the reciprocal of the divisor:

(x+3)(x-1) .............. (x+2)

-------------- .....X......--------------

(x+2)(x-2) .............. (x+6)(x+1)

and solve in normal mathematical fashion with normal multiplication and division rules.

I won't take the answer any farther, haha, I don't mind helping but I'm a teacher and I can never bring myself to give someone an answer.

BTW, ignore the dots, I just added them in there so the formula would space correctly

(x+3)(x-1) .............. (x+2)

-------------- .....X......--------------

(x+2)(x-2) .............. (x+6)(x+1)

and solve in normal mathematical fashion with normal multiplication and division rules.

I won't take the answer any farther, haha, I don't mind helping but I'm a teacher and I can never bring myself to give someone an answer.

BTW, ignore the dots, I just added them in there so the formula would space correctly

#6

(x+3)(x-1) (x+6)(x+1)

-------------- / --------------

(x+2)(x-2) (x+2)

and then you just change it to a multiplication question.

(x+3)(x-1) (x+2)

-------------- x --------------

(x+2)(x-2) (x+6)(x+1)

and solve. I think that's how...

-------------- / --------------

(x+2)(x-2) (x+2)

and then you just change it to a multiplication question.

(x+3)(x-1) (x+2)

-------------- x --------------

(x+2)(x-2) (x+6)(x+1)

and solve. I think that's how...

#7

ok, just forget what i said!

#8

or you can bring the denominator up and make it to the power -1, but im not sure that will be much help. Just times by the reciproca like someone said up there.

#9

(x+3)(x-1) (x+6)(x+1)

-------------- / --------------

(x+2)(x-2) (x+2)

and then you just change it to a multiplication question.

(x+3)(x-1) (x+2)

-------------- x --------------

(x+2)(x-2) (x+6)(x+1)

and solve. I think that's how...

That is right you just need to nustiply top by top and bottom by bottom now.

#10

Thank you reciprocal guy!! I was supposed to learn that a while ago, but somehow I skipped it or something