#1

someone wanna solve these for me???

6x(squared) - x - 12

x(to the 4th power) + 2x(squared) + 1

2x(squared) - 7x - 9

s(cubed) + t(cubed)

8x(to the 6th power) + 14x(cubed) - 15

x(to the 6th power) - y(to the 6th power)

6x(squared) - x - 12

x(to the 4th power) + 2x(squared) + 1

2x(squared) - 7x - 9

s(cubed) + t(cubed)

8x(to the 6th power) + 14x(cubed) - 15

x(to the 6th power) - y(to the 6th power)

#2

no. anyways, you can't do these witbout knowing what to do.

#3

you need to learn little boy. or you'll fail your test

#4

screw that

#5

Are you factoring... solving for 0 products... what the hell are you doing?

#6

Fix those problems to make them easier to read; insert the exponents like this.

2(Squared)=2^2

4(to the sixth power)=4^6

2(Squared)=2^2

4(to the sixth power)=4^6

#7

unless you want me to draw parabolas, no

#8

Fix those problems to make them easier to read; insert the exponents like this.

2(Squared)=2^2

4(to the sixth power)=4^6

Damn, that's too easy for me.

#9

find the root of a side of a cirlce whose circumference is 10 cm, with a radius of 30 cm

#10

find the root of a side of a cirlce whose circumference is 10 cm, with a radius of 30 cm

Is that circle imaginary?

#11

-b +- <square root>b(squared) - 4ac</square root>

------------------------------------------------------------------

2a

there's the formula. a=coefficient of x(squared), b=coefficient of x, c=the other number

------------------------------------------------------------------

2a

there's the formula. a=coefficient of x(squared), b=coefficient of x, c=the other number

#12

find the root of a side of a cirlce whose circumference is 10 cm, with a radius of 30 cm

you dont make sense.........radius is half of the circumference

dumbass

#13

Math sucks, there's too many numbers and stuff.

#14

you dont make sense.........radius is half of the circumference

dumbass

radius is half of the diameter

dumbass

*Last edited by Dimebag22 at Feb 7, 2007,*

#15

-b +- <square root>b(squared) - 4ac</square root>

------------------------------------------------------------------

2a

there's the formula. a=coefficient of x(squared), b=coefficient of x, c=the other number

I don't have an X value to find for a triangle

#16

radius is half of the diameter

ahahahaha

Nice Try Mace.

#17

I don't have an X value to find for a triangle

so are you serious or are you being a dick?

#18

...what do they want you to do? Factor of find the value of x?

#19

you dont make sense.........radius is half of the circumference

dumbass

This has got to be embarrasing for you.

#20

so are you serious or are you being a dick?

Dunno

I know that equation like the back of my hand, but I can't remember the exact application of it.

**Edit-X:**It's to find the X value of a parabola.

#21

you dont make sense.........radius is half of the circumference

dumbass

oh come on, somebody sig that

#22

Dunno

I know that equation like the back of my hand, but I can't remember the exact application of it.

you just plug in all the numbers and it gives you "x"

as long as you remember that equation, you don't have to do any factoring or anything.

#23

oh come on, somebody sig that

my sig is already to full of points to sig that

#24

you just plug in all the numbers and it gives you "x"

as long as you remember that equation, you don't have to do any factoring or anything.

Yeah, I know. I remember it.

But who cares, I don't have to take another math class in my entire life.

#25

Yeah, I know. I remember it.

But who cares, I don't have to take another math class in my entire life.

you, sir, are one lucky bastard

#26

sig what??

#27

Thats pretty basic stuff, you might wanna acaully learn it.

#28

factor completely....

i know how to do it, but i get stuck when you have to have 2 numbers that add to be x(some number) and multiply to another number (also x).... example: 2(x - _)(x+_) no say you have to have 2 numbers that add to be 7 and those same 2 numbers have to multiply to be 9... cant ever find those numbers..

i know how to do it, but i get stuck when you have to have 2 numbers that add to be x(some number) and multiply to another number (also x).... example: 2(x - _)(x+_) no say you have to have 2 numbers that add to be 7 and those same 2 numbers have to multiply to be 9... cant ever find those numbers..

#29

I showed you how to do it right, but whatever. Here: http://mathworld.wolfram.com/QuadraticEquation.html

#30

find the root of a side of a cirlce whose circumference is 10 cm, with a radius of 30 cm

I could have missed this in Geometry or Alg II, but how is the circumference smaller than the radius if cirfumference=2Pir

Pi=Pi

r=Radius

#31

well the first one is something like (3x+4)(2x-3). I'm going to give you anymore and it'd be nice if someone could even check that answer haha.

#32

I could have missed this in Geometry or Alg II, but how is the circumference smaller than the radius if cirfumference=2Pir

Pi=Pi

r=Radius

C= It's 2Pir^2

#33

C= It's 2Pir^2

No area isA=(Pi)(r^2) while circumference is C=(2)(pi)(r) or rather C=(D)(Pi);D being diameter.

#34

No area isA=(Pi)(r^2) while circumference is C=(2)(pi)(r) or rather C=(D)(Pi);D being diameter.

Damnit, that's right. Oh well

#35

C= It's 2Pir^2

no. wrong.

circumference = 2Pir

area = Pir^2

EDIT: damn, beat me to it.

#36

(3x+4)(2x-3). = wrong. thanks for trying though...

#37

someone wanna solve these for me???

6x(squared) - x - 12

x(to the 4th power) + 2x(squared) + 1

2x(squared) - 7x - 9

s(cubed) + t(cubed)

8x(to the 6th power) + 14x(cubed) - 15

x(to the 6th power) - y(to the 6th power)

None of these mean anything. At all. To anyone. You need to learn the difference between "expression" and "equation". An expression with a variable means nothing. You're basically saying "Solve 'x' ". In case you're confused about math, that's less sensical than saying "Solve 3". Now the difference is, if you gave us, say, "Solve x=0", or "Solve 3x^2-1=2", this can actually be done. You have an equation, an equation from which you can derive an answer. There's only going to be, in general, a finite number of solutions for one variable in an equation with one variable. Even if you get "x=3^z(y-1)", there's still going to be, in general, 1 or 2 or whatever finite or describable set of values for x given every z and y.

#38

Damnit, that's right. Oh well

Its all good. The only reason I can remember that is because I'm doing SAT prep and I've had to do a few of those problems.

#39

(3x+4)(2x-3). = wrong. thanks for trying though...

alright, so it's a different kind of factoring. What's the answer the book gives you?

#40

FACTOR THEM COMPLETELY.... i left that out sorry. that means somthing... all those can be factored out...