#1

well ive got a maths exam that we had to do for homework and i have school in 20 mins lol how do i do this question??? (4x-3y)(2x+y)-(3x-4y)(2x+y) it says to simplify by expanding and collecting like terms.

thanks.

thanks.

#2

I have no idea but I wish you luck m8. Well done for getting it done earlier

#3

just open up the brackets and then put the Xs on one side and the Ys on the other side.

#4

5x-5y

#5

math! you unholy bastard! i dont know im in stoopid maf

#6

Wait how doyou have school in 5 minutes

where do you live?

it's like 5:48 PM where i'm at..

on topic

I think luthier did it right

where do you live?

it's like 5:48 PM where i'm at..

on topic

I think luthier did it right

#7

it has answers but everytime i try and do it i get it rong and the teacher says to sho working and shit and 5x-5y is rong the sheet says answer is 2x(squared) + 3xy + y(squared)

#8

(4x-3y)(2x+y)-(3x-4y)(2x+y)

8x^2 + 4xy - 6xy - 3y^2

8x^2 - 2xy - 3y^2

2x^2 - 3xy + y^2

It makes sense to me. But I don't do maths, so I made it up. If I'm right, I invented it.

8x^2 + 4xy - 6xy - 3y^2

**-**6x^2 + 3xy - 4xy - 4y^28x^2 - 2xy - 3y^2

**-**6x^2 - xy - 4y^22x^2 - 3xy + y^2

It makes sense to me. But I don't do maths, so I made it up. If I'm right, I invented it.

#9

Well then your answer sheet is wrong. Im doing this in College Algebra and just had a test over it Thursday. The way I did it is correct. Maybe you need to talk to your teacher about it, because their obviously feeding you some wrong shit.

#10

yopu have to use the distributive property of multiplication distribute the 4x to every other x and multiply them together and ten ADD the y's then fit the anser to how many x's you got into where the x is its called substitution

#11

(4x-3y)(2x+y)-(3x-4y)(2x+y)

Well if you do it by multiplying you get:

4x*2x= 8x

-3y*y= -3y

So the first part would be: 8x-3y

Second part would be:

3x*2x= 6x

-4y*y= -4y

So second is 6x-4y

Whole thing is 8x-3y-6x-4y

So then to combine like terms you would get:

8x-6x= 2x

-3y-4y= -7y

So:

2x-7y

But your answer sheet still is wrong, according to me. So I think your answer sheet is wrong.

Well if you do it by multiplying you get:

4x*2x= 8x

-3y*y= -3y

So the first part would be: 8x-3y

Second part would be:

3x*2x= 6x

-4y*y= -4y

So second is 6x-4y

Whole thing is 8x-3y-6x-4y

So then to combine like terms you would get:

8x-6x= 2x

-3y-4y= -7y

So:

2x-7y

But your answer sheet still is wrong, according to me. So I think your answer sheet is wrong.

#12

Yay! I got it right! I could make it more clear if you don't understand. ^2 = squared, just so you know.

#13

*sigh*

I remember when Math was this easy...

I remember when Math was this easy...

#14

Check your math, his book answer is correct.

(4x-3y)(2x+y)-(3x-4y)(2x+y)

Well if you do it by multiplying you get:

4x*2x= 8x

-3y*y= -3y

So the first part would be: 8x-3y

Second part would be:

3x*2x= 6x

-4y*y= -4y

So second is 6x-4y

Whole thing is 8x-3y-6x-4y

So then to combine like terms you would get:

8x-6x= 2x

-3y-4y= -7y

So:

2x-7y

But your answer sheet still is wrong, according to me. So I think your answer sheet is wrong.

#15

Wow... Holy shit. I forgot how to do this.

#16

you FOIL it into *quadratic equation* minues *another quadratic equation*, and then subtract. i dont feel like doing the actual work, but thats how you do it

#17

We use FOIL too

#18

(4x-3y)(2x+y)-(3x-4y)(2x+y)

Well if you do it by multiplying you get:

4x*2x= 8x

-3y*y= -3y

So the first part would be: 8x-3y

Second part would be:

3x*2x= 6x

-4y*y= -4y

So second is 6x-4y

Whole thing is 8x-3y-6x-4y

So then to combine like terms you would get:

8x-6x= 2x

-3y-4y= -7y

So:

2x-7y

But your answer sheet still is wrong, according to me. So I think your answer sheet is wrong.

You're wrong.

(4x-3y)(2x+y)-(3x-4y)(2x+y)

(4x*2x + 4x*y + -3y*2x + -3y + y) - (3x*2x + 3x*y + -4y*2x + -4y*y)

(8x^2 + 4xy - 6xy - 3y^2) - (6x^2 + 3xy - 8xy - 4y^2)

(8x^2 - 2xy -3y^2) - (6x^2 - 5xy - 4y^2)

8x^2 - 2xy - 3y^2 - 6x^2 + 5xy + 4y^2

8x^2 - 6x^2 - 2xy + 5xy - 3y^2 + 4y^2

2x^2 + 3xy + y^2

#19

Alright. Gibsonpenguin. I can admit when Im wrong. Just seems wierd to me though.

BTW< TS, are you studying physics or something? Cause that shit is ridiculous. You will NEVER need that anywhere other then in a room full of dudes with pocket protectors.

BTW< TS, are you studying physics or something? Cause that shit is ridiculous. You will NEVER need that anywhere other then in a room full of dudes with pocket protectors.

#20

Alright. Gibsonpenguin. I can admit when Im wrong. Just seems wierd to me though.

BTW< TS, are you studying physics or something? Cause that shit is ridiculous. You will NEVER need that anywhere other then in a room full of dudes with pocket protectors.

Sorry, I didn't mean to sound like an asshole or anything.

No offense or anything, but I learned this stuff in like 10th grade Algebra 2. You were close with what you were doing, but you skipped a couple steps. The way we learned it was called FOIL. Which stands for First, Outer, Inner, Last. So if you are multiplying these two things:

(w + x) * (y + z)

You do the first of each set of parentheses:

wy

Plus the outer amounts:

wz

Plus the inner amounts:

xy

Plus the last amounts of each set of parentheses:

xz

Total:

wy + wz + xy + xz

Then you can combine like terms and simplify (when you're using numbers and less variables). It's also a lot more useful than you seem to think it is.