#1

i need to know what the variables q=mc delta t stand for, i have an exam over it tommorow and i have no clue what this formula is....i was absent the day we went over it in class....thanks

Edit: in the equation the delta is a trinagle...if that helps at all

Edit: in the equation the delta is a trinagle...if that helps at all

#2

From yahoo answers...

Q = m*c*(delta T)

Q = heat energy

m = mass

c = specific heat

delta t = change in temperature (= final - initial temp)

Q = m*c*(delta T)

Q = heat energy

m = mass

c = specific heat

delta t = change in temperature (= final - initial temp)

#3

I believe m is for mass, c is heat capacity, and delta t is average temperature..hope that helps.

#4

McDelta T. It's a sandwich at McDonald's, and it's endorsed by Mr. T. He wants to show how he's changed over the years, and how now he caters the foo'.

#5

so then when you "plug in" the variables, do you just multiply them all togther or multiply mc and devide by delta t????

#6

Multiply

#7

all of them?

#8

Yup..that solves for Q

#9

From yahoo answers...

Q = m*c*(delta T)

Q = heat energy

m = mass

c = specific heat

delta t = change in temperature (= final - initial temp)

yep, q=heat

m=mass

C=spec. heat

delta t = change in temp (Tf-Ti)

and you can set them equal to each other for a system...

mCdelta t = mCdelta t

#10

From yahoo answers...

Q = m*c*(delta T)

Q = heat energy

m = mass

c = specific heat

delta t = change in temperature (= final - initial temp)

That is correct, after multiplying MC and Delta T you'll have the amount of heat energy (in Joules) that is absorbed (+ answer) or released (- answer) in a given reaction. If M C or Delta T is the unknown variable take the necessary algebraic steps to solve for it (I'm assuming you passed algebra since you're in chemistry).

*Last edited by NGD1313 at Feb 25, 2007,*