#1

Im about ready to punch a baby because I have no clue what im trying to do. But anyways, heres to you, The Pit.

I have to solve this problem by either using the elimination method or the substitution method. Heres the problem

I own a used car lot. The total value of the lot equals $2,997,600 and I have 150 vehicles on site. I already know that I have 22 trucks, and they sell for $22,300. The cars I have for sell for are $17,500 and then mini vans I have for sale are $26,400. I need to find out how many cars/vans are on the lot by this info.

(BTW, Im trying to get the biggest bang for my buck, Ive come out with a couple different numbers but Ive had some money left over)

The equations Ive come up with so far is 17500C+26400V=2507000 ( I eliminated the total price of the trucks from the total price of the lot) and C+V=128 (the 22 trucks subtracted from that)

Any help at all is greatly appreciated.

I have to solve this problem by either using the elimination method or the substitution method. Heres the problem

I own a used car lot. The total value of the lot equals $2,997,600 and I have 150 vehicles on site. I already know that I have 22 trucks, and they sell for $22,300. The cars I have for sell for are $17,500 and then mini vans I have for sale are $26,400. I need to find out how many cars/vans are on the lot by this info.

(BTW, Im trying to get the biggest bang for my buck, Ive come out with a couple different numbers but Ive had some money left over)

The equations Ive come up with so far is 17500C+26400V=2507000 ( I eliminated the total price of the trucks from the total price of the lot) and C+V=128 (the 22 trucks subtracted from that)

Any help at all is greatly appreciated.

*Last edited by Mexican Militia at Mar 4, 2007,*

#2

#3

multiply $22,300 by 22 then subtract that from $2,997,600.

Then

i dunno im too tired to work it out.

Then

i dunno im too tired to work it out.

#4

17500C+26400V=2507000 -- Solve for either variable, then

Plug into here, solve for that variable

C+V=128

plug back in

V= (2507000- 17500C)/26400

C + ((2507000-17500C)/26400)= 128

Solve for C

plug C back into C+V=128

solve for V

Plug into here, solve for that variable

C+V=128

plug back in

V= (2507000- 17500C)/26400

C + ((2507000-17500C)/26400)= 128

Solve for C

plug C back into C+V=128

solve for V

*Last edited by Mr_Bluesman at Mar 4, 2007,*

#5

multiply $22,300 by 22 then subtract that from $2,997,600.

Then

i dunno im too tired to work it out.

Sounds like linear systems to me i'll work it out and post the answer

#6

just pay some kid to count them, duh

#7

I got 98 cars and 30 minivans as the answer do you need me to explain it?

edit: it might be wrong actually let me double check

2edit: No it's right and as for the explanation the guy below me has it

edit: it might be wrong actually let me double check

2edit: No it's right and as for the explanation the guy below me has it

*Last edited by lemon at Mar 4, 2007,*

#8

Lemon and stained would be correct.

#9

I agree with this guy^^

You have 98 cars and 30 Vans to get the remaining $2507000.

(98*17500)+(30*26400)=2507000

I used excel, so I can't help with the elimination method. In order to get the "the most bang for your buck", you would just sell vans. 150*26400.

You have 98 cars and 30 Vans to get the remaining $2507000.

(98*17500)+(30*26400)=2507000

I used excel, so I can't help with the elimination method. In order to get the "the most bang for your buck", you would just sell vans. 150*26400.

#10

Im going to make out with you lemon and then im going to let you give anal.

I love you.

I love you.