#2
e^u du

so:
Quote by Gaz_m2k5
Quick maths:
8e^(4x)
or
-3e^(3x/2)


32e^(4x)
and
-(9/2)e^(3x/2)


Shit. I think I just dy/dx'd it. sorry. But it has to be in that form

so for the first, you pull out the 8, then multiply by 1/4 so 2e^(4x)

-2e^(3x/2)

I believe.
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Last edited by rbmason at Mar 7, 2007,
#4
I hate Calculus. I wish I could help you, but I'm not sure we've gotten that in depth with e^x functions yet.
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