#1
I've got a cabinet that was orginally 4x12, but was converted to a 2x12. The speakers are [two] celestion vintage 30's, 16 ohms each.

Quote by chase312

And, the way the cab is wired now is like this:

(pos +)----- [speaker 1]---[+]---[speaker 2]
(neg -)-------[speaker 1]---[-]---[speaker 2]
(both 16 ohms)

If that isnt clear.. The positive lead from the jack goes to the positive terminal on speaker 1, and from there it goes to speaker 2. The negative does the same. Each lead goes to two speakers.

So this should be an 8 ohms cab, right?


And if I wired it in series-parallel with two more 16 ohm speakers, would the impedance be 16 ohms?
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Last edited by chase312 at Mar 14, 2007,
#2
With that configuration, you can get either 4, 9.3 or 16 ohms, it all depends what your head takes.
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#3
Edited above question.
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Last edited by chase312 at Mar 14, 2007,