#1

Sodium chloride is produced from its elements through a synthesis reaction. What mass of each reactant would be required to produce 25.0 mol of sodium chloride?

Can someone please solve this problem? I need to check my answer to make sure I did it right.

Can someone please solve this problem? I need to check my answer to make sure I did it right.

#2

Sodium chloride is produced from its elements through a synthesis reaction. What mass of each reactant would be required to produce 25.0 mol of sodium chloride?

Can someone please solve this problem?I need to check my answer to make sure I did it right.

ok then, whats

**your**answer?

#3

12.5 i think

oh, in grams

287.5 g Na

443.75 g Cl

oh, in grams

287.5 g Na

443.75 g Cl

#4

RAM of Na = 23

RAM of Cl = 35.5

Ratio 1:1

Mole = Mass/RAM

12.5 = Mass/23 for Na

12.5 = Mass/35.5 for Cl

287.5g Na

443.75g Cl

I think...

RAM of Cl = 35.5

Ratio 1:1

Mole = Mass/RAM

12.5 = Mass/23 for Na

12.5 = Mass/35.5 for Cl

287.5g Na

443.75g Cl

I think...

#5

MTV and ChubbyChunks, you guys must've gotten it right since you got the same answer. I got 143.69g Na. Can one of you explain how you got it?

#6

Well I did explain. And he copied me

#7

Well you'd need 25 mols of Na and 25 mols of Cl. 25x23=575g for Na and 25 x 35.5= 887.5 for Cl.

EDIT: I'm pretty sure you need 25 mols of Na to make 25 mols of NaCl. . .

EDIT: I'm pretty sure you need 25 mols of Na to make 25 mols of NaCl. . .

#8

Oh. I'm not quite following your explanation well. I use the conversion chart for this.

#9

Well you'd need 25 mols of Na and 25 mols of Cl. 25x23=575g for Na and 25 x 35.5= 887.5 for Cl.

EDIT: I'm pretty sure you need 25 mols of Na to make 25 mols of NaCl. . .

2Na+Cl^2-->2NaCl

It's 1 to 1 for Na.

But, it's 1 to 2 for Cl. And Cl's molar mass is 35.4527.

#10

This is tenth grade science, haha.

#11

Mass = Mol x RAM

Mass NaCl = 25 x(22.99+35.45)]

Mass NaCl = 1461 g

Reaction:

Na + 1/2Cl2 --> NaCl

Reaction ratio 1:1 therefore if you make 25 Mol of product you would need 25 mol of Na and 12.5 mol of Cl2 (think about it, 12.5 mole of Cl2 is the same as 25 mol Cl on its own).

So:

Mass Na = 25x22.99 = 574.75 g

Mass Cl2 = 1/2 x 2 x 25 x 35.45 = 886.25g

Total Mass NaCl = 1461 g

Which is the mass at the start.

Mass NaCl = 25 x(22.99+35.45)]

Mass NaCl = 1461 g

Reaction:

Na + 1/2Cl2 --> NaCl

Reaction ratio 1:1 therefore if you make 25 Mol of product you would need 25 mol of Na and 12.5 mol of Cl2 (think about it, 12.5 mole of Cl2 is the same as 25 mol Cl on its own).

So:

Mass Na = 25x22.99 = 574.75 g

Mass Cl2 = 1/2 x 2 x 25 x 35.45 = 886.25g

Total Mass NaCl = 1461 g

Which is the mass at the start.

*Last edited by Guitardude19 at Mar 12, 2007,*

#12

Mass = Mol x RAM

Mass NaCl = 25 x(22.99+35.45)]

Mass NaCl = 1461 g

Reaction:

Na + 1/2Cl2 --> NaCl

Reaction ratio 1:1 therefore if you make 25 Mol of product you would need 25 mol of Na and 12.5 mol of Cl2 (think about it, 12.5 mole of Cl2 is the same as 25 mol Cl on its own).

So:

Mass Na = 25x22.99 = 574.75 g

Mass Cl2 = 1/2 x 2 x 25 x 35.45 = 886.25g

Total Mass NaCl = 1461 g

Which is the mass at the start.

All right. That makes sense. Thanks.

This is tenth grade science, haha.

Yeah, and you obviously know how to do it, considering that you offered so much help.

#13

Well you'd need 25 mols of Na and 25 mols of Cl. 25x23=575g for Na and 25 x 35.5= 887.5 for Cl.

EDIT: I'm pretty sure you need 25 mols of Na to make 25 mols of NaCl. . .

+1

you need 25 moles of each. I'm assuming your arithmetic is correct, I can't be bothered to do it. But the principle is correct.

EDIT: crap. you only need half the number of moles for Cl2 (chlorine gas).

So you need 12.5 moles of Cl2, and 25 moles of sodium. you should be able to work it out from there.

#14

Mass = Mol x RAM

Mass NaCl = 25 x(22.99+35.45)]

Mass NaCl = 1461 g

Reaction:

Na + 1/2Cl2 --> NaCl

Reaction ratio 1:1 therefore if you make 25 Mol of product you would need 25 mol of Na and 12.5 mol of Cl2 (think about it, 12.5 mole of Cl2 is the same as 25 mol Cl on its own).

So:

Mass Na = 25x22.99 = 574.75 g

Mass Cl2 = 1/2 x 2 x 25 x 35.45 = 886.25g

Total Mass NaCl = 1461 g

Which is the mass at the start.

why did you multiply the 1/2 by 2 in the Cl2 bit?

#15

He multiplied it by 2 because of the subscript.

#16

garg, I'm starting from scratch here (i can't edit or my computer will crash).

the mass of NaCl is 23 + 35.5 =58.5. Multiply by the number of moles (25) gives you 1462.5 grams.

You need 25 moles of sodium, which is 25 x 23 = 575g.

you need 25 moles of Cl; however chlorine in its natural form is Cl2, so you only need 12.5 moles of this.

12.5 x 71 (the mass of the chlorine molecule (i realise why that guy multiplied by two above now, apologies )) = 887.5g of Chlorine.

I think that's it. So yeah, that guy above was right.

the mass of NaCl is 23 + 35.5 =58.5. Multiply by the number of moles (25) gives you 1462.5 grams.

You need 25 moles of sodium, which is 25 x 23 = 575g.

you need 25 moles of Cl; however chlorine in its natural form is Cl2, so you only need 12.5 moles of this.

12.5 x 71 (the mass of the chlorine molecule (i realise why that guy multiplied by two above now, apologies )) = 887.5g of Chlorine.

I think that's it. So yeah, that guy above was right.

#17

He multiplied it by 2 because of the subscript.

yeah, i got it. I'd have done that in my head, that's why I missed it. I did it from scratch again just to make sure it was correct.

#18

garg, I'm starting from scratch here (i can't edit or my computer will crash).

the mass of NaCl is 23 + 35.5 =58.5. Multiply by the number of moles (25) gives you 1462.5 grams.

You need 25 moles of sodium, which is 25 x 23 = 575g.

you need 25 moles of Cl; however chlorine in its natural form is Cl2, so you only need 12.5 moles of this.

12.5 x 71 (the mass of the chlorine molecule (i realise why that guy multiplied by two above now, apologies )) = 887.5g of Chlorine.

I think that's it. So yeah, that guy above was right.

So was me.

#19

Sodium chloride is produced from its elements through a synthesis reaction. What mass of each reactant would be required to produce 25.0 mol of sodium chloride?

Can someone please solve this problem? I need to check my answer to make sure I did it right.

k i know im gonna b flamed 4 this but what is stoichiometry

#20

^^ yeah. you actually didn't need to bother with the converting the Cl to Cl2 guff as long as they asked you for weight, not moles. And didn't award marks for working out.

EDIT: stoichiometry is basically the ratios of reactants to each other.

EDIT: stoichiometry is basically the ratios of reactants to each other.

#21

^^You won't get flamed, people here aren't complete assholes...

Its like asking what... something I've never heard of is...... ...

I had a real "Stoichiometry.. that's right up my alley" moment,

then I remembered that I pay no attention in college and I no longer do chemistry..

Its like asking what... something I've never heard of is...... ...

I had a real "Stoichiometry.. that's right up my alley" moment,

then I remembered that I pay no attention in college and I no longer do chemistry..

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