#1

if something is to the negative exponent, how do you go about solving it?

for example im giving an equation such as y = 6x divided by x(-2) + 1

(-2) being the exponent

so if i was to plug in 2 for example, how would you do 2 to the -2?

thanks in advance

for example im giving an equation such as y = 6x divided by x(-2) + 1

(-2) being the exponent

so if i was to plug in 2 for example, how would you do 2 to the -2?

thanks in advance

#2

If I remember right you have to move it to the demenator and it makes the exponent positive and you do it from there. So with 2 it would be 1/4 I think.. just guessing though.

#3

2^-1 means 1/2

so 2^-2 means 1/2^2 ie 1/4

so 2^-2 means 1/2^2 ie 1/4

#4

put the negative exponent into the denominator.

so instead of x(-2) you have 1/x(2)

so instead of x(-2) you have 1/x(2)

#5

to solve a negative exponent, solve the exponent then find the reciprocal, so 2^-2 would be 1 over 4, and 3^-3 would be 1 over 27

#6

6x^3/ ((x+1)*(x-1))

#7

i dont start school til tomorrow ask me then.

#8

y = 6x divided by x(-2) + 1

x = 2, so:

y = 6(2) / 2(-2) + 1

y = 12 / -4 + 1

y = 9

x = 2, so:

y = 6(2) / 2(-2) + 1

y = 12 / -4 + 1

y = 9

#9

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#10

woh sweet!

anyone want to help me with MY maths homework tonight?

anyone want to help me with MY maths homework tonight?