#1
Hey, here the question I need help with:
Make a table, draw a graph, and write an equation for this sequence. The predict the 200th term:
5, 11, 17, 23

i get all of it except how do you make a grpah with only 4 #s? thanks in advance.
Make a table, draw a graph, and write an equation for this sequence. The predict the 200th term:
5, 11, 17, 23

i get all of it except how do you make a grpah with only 4 #s? thanks in advance.
#2
Hey, here the question I need help with:
Make a table, draw a graph, and write an equation for this sequence. The predict the 200th term:
5, 11, 17, 23

i get all of it except how do you make a grpah with only 4 #s? thanks in advance.
You need coordinates for a graph and those don't look like fucking coordinates to me.
#3
You need coordinates for a graph and those don't look like fucking coordinates to me.
http://en.wikipedia.org/wiki/Sequence
and in your case
http://en.wikipedia.org/wiki/Arithmetic_progression
#4
They go up by 6.
y=6n
To get it to the numbers, you need to take away 1.
So y=6x1. I think.
First term, x=1
y=5
200th term, x=200
y=1199
y=6n
To get it to the numbers, you need to take away 1.
So y=6x1. I think.
First term, x=1
y=5
200th term, x=200
y=1199
#5
never mind, just htink my teachers retarded.
#6
the coordinates are the numbers you have on the y and the x values is the number of the term you are talking about like those numbers would be (1,5) (2,11) (3, 17) (4,23). The simplest solution to the pattern is just add 6 to the previous value. This gives you a slope of 6/1 (rise/run). You just plot 2 of the coordinates you have their and draw a straight line connecting them. The line will have a slope of 6. Equation in slopeint form> y=6x
plug in 200 for x and you have the 200th term
plug in 200 for x and you have the 200th term
#7
I stand corrected.