#1

can you do this problem for me..and explain to me how you did it please?

you have to simplify the following fraction..

you have to simplify the following fraction..

#2

Just type it here for us, that'll be easier

Edit: I get b^4/6a^3

...but that's quick and in my head and the writing isn't the easiest to read. Write it out in full, see what cancels out, cancel the negatives, and divide the numbers like you normally would.

Edit: I get b^4/6a^3

...but that's quick and in my head and the writing isn't the easiest to read. Write it out in full, see what cancels out, cancel the negatives, and divide the numbers like you normally would.

*Last edited by bequickorbedead at Sep 12, 2007,*

#3

Just type it here for us, that'll be easier

its hard to because of the exponents and the line.

i just resized the pic.

#4

whats the power of the b in the numerator? it looks like 4.

amirite?

amirite?

#5

whats the power of the b in the numerator? it looks like 4.

amirite?

It's 6

#6

whats the power of the b in the numerator? it looks like 4.

amirite?

6.

#7

divide -3 by -18 and subtract exponents.

#8

a^-3 b^4

----------

6

edit:actually the guy below me is right, too, and your teacher might want his version.

----------

6

edit:actually the guy below me is right, too, and your teacher might want his version.

*Last edited by catchy phrase at Sep 12, 2007,*

#9

b^4 / 6 a^3

#10

yup 6a^-3b^4

#11

Ok. First off, you can divide -3 and -18 both by -3 to get 1/6, without the exponents. For the exponents, whatever base is raised to the largest power, you subtract the smaller power. For example, a^2/a^7 is 1/a^7-2, or a^5. You keep the base variable on the side of the fraction bar that the larger power was on, if that makes sense. I end up getting 1b^4/6a^3

#12

I'm sorry but...I really don't think you need UG's help for this.

This is like 5th or 6th grade math dude. Figure it out yourself.

This is like 5th or 6th grade math dude. Figure it out yourself.

#13

bequickorbedead (first guy) is right. catch prase isn't. it's b^4/6a^3

Guys like me who are good at math can do that in their head.

Guys like me who are good at math can do that in their head.

#14

b^4 / 6 a^3

someone tell me how

#15

I'm sorry but...I really don't think you need UG's help for this.

This is like 5th or 6th grade math dude. Figure it out yourself.

You take algebra in 6th grade? Lies.

EDIT:

someone tell me how

I did!

#16

I'm sorry but...I really don't think you need UG's help for this.

This is like 5th or 6th grade math dude. Figure it out yourself.

actaully..

im in 10th grade, this is algebra 2.

#17

Just type it here for us, that'll be easier

Edit: I get b^4/6a^3

...but that's quick and in my head and the writing isn't the easiest to read. Write it out in full, see what cancels out, cancel the negatives, and divide the numbers like you normally would.

this is the right answer...

#18

```
-3b^4(a^2*b^2)
------------
-18a^3(a^2*b^2)
```

cancel the -(a^2*b^2)

so you have

```
3b^4
----
18a^3
```

then you can divide by 3 too

```
b^4
---
6a^3
```

I think that's right.

#19

actaully..

im in 10th grade, this is algebra 2.

Same here. We're taking this right now, too.

#20

nice handwriting...mine sucks

#21

actaully..

im in 10th grade, this is algebra 2.

Ha! im in 9th grade and taking algebra 2!

/bragging

i skipped a grade of math and im taking it with sophomores. it sucks....

#22

okay. i see how you guys got that answer. just divided the -18 and the -3 by -3. and just subtracted the powers. thanks.

#23

okay. i see how you guys got that answer. just divided the -18 and the -3 by -3. and just subtracted the powers. thanks.

Hooray! Pretty easy once you get the hang of it.

#24

okay. i see how you guys got that answer. just divided the -18 and the -3 by -3. and just subtracted the powers. thanks.

dont subtract the powers you cancel them... big difference and one that can lead you into bad habits.

#25

ha im in ninth grade and im in algebra 2 TRIG

#26

Hooray! Pretty easy once you get the hang of it.

yeah. thanks.

#27

dont subtract the powers you cancel them... big difference and one that can lead you into bad habits.

what do you mean cancel them? i thought you just take the larger power and subtract it by the smaller one.

#28

ha im in ninth grade and im in algebra 2 TRIG

i have a friend whos in 9th grade taking pre-calculus. oh! i indirectly pwned you!

but like the other guy said, make sure you

*cancel*out exponents instead of just subtracting them.

Edit: ^Make sure that whichever is bigger stays. like if you have an a^3 on top and an a^2 on bottom its just a but if you have an a^2 on top and an a^3 on bottom its 1 over a. follow?

#29

dont subtract the powers you cancel them... big difference and one that can lead you into bad habits.

It's the same thing, that's how we were taught to divide powers. It's the same as doing

(a*a*a*a*a)/(a*a*a) and cancelling out to get a*a, or a^2, it's just easier to say a^5-3

#30

okay..i have one more. this ones really easy, and im positive my answers right. but my teacher says its wrong.

simplify and solve..

12-5(2w-13)=3(2w-5)

i got 9.5, im pretty sure thats right.

simplify and solve..

12-5(2w-13)=3(2w-5)

i got 9.5, im pretty sure thats right.

#31

what do you mean cancel them? i thought you just take the larger power and subtract it by the smaller one.

that might be what you do visually but that's not what your doing mathematically.

the same way the 3/3 cancels out to 1/1=1

x/x cancels to 1/1=1

```
x^5 x*x*x*x*x
--- = -----------
X^6 x*x*x*x*x*x
```

so if you take them to be 5 sets of x/x and one 1/x

the x/x cancel out to be one and you're left with the 1/x

the quick way to do it visually is to subtract it, but if you get used to doing it that way you might have trouble later on when doing more complex stuff

#32

actaully..

im in 10th grade, this is algebra 2.

They're reviewing it. You're taught this in 5th/6th grade.

And. I'm in pre calc. So. I win.

#33

okay..i have one more. this ones really easy, and im positive my answers right. but my teacher says its wrong.

simplify and solve..

12-5(2w-13)=3(2w-5)

i got 9.5, im pretty sure thats right.

expand then group the terms

12-10w+65=6w-15

93=16w

w=93/16=5.8125

#34

They're reviewing it. You're taught this in 5th/6th grade.

And. I'm in pre calc. So. I win.

No. i actaully learned this last year..in 9th grade. and there reviewing it from that.

twat..

#35

ummm finite math anyone?

#36

expand then group the terms

12-10w+65=6w-15

93=16w

w=93/16=5.8125

Shouldn't it be w=92/16, as 12+65+15 is 92?

It works out to 5.75 if it's 92/16, which I think it is.

#37

expand then group the terms

12-10w+65=6w-15

93=16w

w=93/16=5.8125

whered you get 93??

dont i just use the distributive property and multiply5 by 2w and 13.

oooooh nevermind. i think i forget to add like terms (12 + 65) on the left side.

*Last edited by evan1234567 at Sep 12, 2007,*

#38

okay..i have one more. this ones really easy, and im positive my answers right. but my teacher says its wrong.

simplify and solve..

12-5(2w-13)=3(2w-5)

i got 9.5, im pretty sure thats right.

You use the distributive property to get 12-10w+65 = 6w-15.

add 10w to both sides and add 15 to both sides to get. 92=16w. Divide both sides by 16 to get w by itself, and 92/16 = 5.75

#39

the answer is 5.75.

i see what i did wrong.

math = not my best subject.

i see what i did wrong.

math = not my best subject.

#40

You use the distributive property to get 12-10w+65 = 6w-15.

add 10w to both sides and add 15 to both sides to get. 92=16w. Divide both sides by 16 to get w by itself, and 92/16 = 5.75

Yes. i just wasnt adding the two numbers on the left side. i got itn ow though.