I greatly need some help with my Algebra homework. These are the main ones I'm having problems with. It says to find the slope and y-intercept.

EDIT!!!

Oh, and anyone who needs help with math can post here for questions from now on too.

Fav

EDIT: Okay i have a new question(Check last post)
Last edited by fav13andac1)c at Sep 27, 2007,
slope=m
m=Change in y over the change in x.
if you have a graphing calculator, go to y=, and type it in
The easiest way to do that would be to put the equations into slope-intercept form, which basically means solve for y in terms of x. So, for the first one, you'd add 4y to both sides, add 3 to both sides, and end up with 4y=7x+3. Divide by 4 to get y by itself, and you have slope-intercept form, in this case y=7/4x+3/4. The coefficient before x is your slope (in this case 7/4) and the number afterwards is your y-intercept (3/4.)
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Rearrange to get them in the form of y = mx + c

m is the slope.

c is the y axis intercept.

so first one:

7x-4y=-3
4y = 7x + 3
y = (7/4)x + (3/4)
compare to y = mx + c shows m = 7/4 and c (intercept) = 3/4

Edit: Beaten to it ^
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whoa these ppl are smart. hey man what grade math is that? grade 10? or 11? and um im confused i need to learn that stuff...
y=mx+b. M is your slope, b is your y-intercept. Then you just have to isolate your y and you've got er.
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I'm not really that great with Algebra, but the slope is y=mx+b. oh and if you don't get any of the other posts, you can go to google to find the answer. I've done it before
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whoa these ppl are smart. hey man what grade math is that? grade 10? or 11? and um im confused i need to learn that stuff...

10 or 11? I learned this stuff in 7th grade.

But yeah, use y = mx + b form. And in case nobody has mentioned it, the line y = 8 has a slope of 0. Horizontal lines have a slope of 0 and vertical lines have an undefined slope.
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Last edited by Zeppelin256 at Sep 12, 2007,
Quote by Axeman99
Rearrange to get them in the form of y = mx + c

m is the slope.

c is the y axis intercept.

so first one:

7x-4y=-3
4y = 7x + 3
y = (7/4)x + (3/4)
compare to y = mx + c shows m = 7/4 and c (intercept) = 3/4

Edit: Beaten to it ^

if you rearranged it, wouldnt the 4y remain negative?
^ Yeah, but you divide by -4, so the 7/4 and 3/4 will become positive.
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"If I die, you are forgiven."
Such is the rule of honour.
y=mx + b
Slope formula!
i take art, in a college, so im gonna say the answer is MATH ISNT REAL ITS A CONSPIRACY

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Quote by Zeppelin256
10 or 11? I learned this stuff in 7th grade.

But yeah, use y = mx + b form. And in case nobody has mentioned it, the line y = 8 has a slope of 0. Horizontal lines have a slope of 0 and vertical lines have an undefined slope.

holy! wtf? 7th grade? wait wait wait is this the slope- rise/run thingy? cause now im getting worried, im gonna choke next semister wen my math class starts
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y=mx + b
Slope formula!

Slope intercept form fails in comparison to point-slope form.

y - y0 = m(x - x0)

Slope-intercept is where it's at.
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i learned it in 7th grade too.

use slope intercept form y =mx + b.

im in algebra 2 trig now. its confusing as hell.
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I never really liked math till I got to Calculus. The real-life applications in Calculus made me totally love math, especially the vector-calc part.
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Quote by darkstar2466
Slope intercept form fails in comparison to point-slope form.

y - y0 = m(x - x0)

Slope-intercept is where it's at.

Yeah, that's the way to go
I just realized the mistake in my post. It's supposed to say "Point-slope is where it's at."
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
I learned this stuff in 7th grade too and now I am starting calculus in 11th grade.
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10 or 11? I learned this stuff in 7th grade.

Same here man.... it amazes me how kids these days completely fail maths.

Incredible!
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Same here man.... it amazes me how kids these days completely fail maths.

Incredible!

In my high school there were sophomores taking basic algebra. Many of my classmates learned that stuff in 5th grade. It's ridiculous.
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Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie
ok quick question

let's see:

2(3x-3)<6(x-1)
break down
6x-6<6x-6
add 6 to both - sixes
6x<6x
divide both sides by 6

Quote by fav13andac1)c
ok quick question

let's see:

2(3x-3)<6(x-1)
break down
6x-6<6x-6
add 6 to both - sixes
6x<6x
divide both sides by 6