#1

A World Series batter hits a home run ball with a velocity of 40 m/s at an angle of 26 degrees above the horizontal. A fielder who can reach 3.0 m above the ground is backed up against the bleacher wall, which is 110 m from home plate. The ball was 120 cm above the ground when hit. How high above the fielder's glove does the ball pass?

#2

That's a quadratic function if I'm not mistaken (although I very well may be. I'm an English/History man myself).

#3

Dude that's so easy. I know cuz my physics class lat year kept saying that for those knd of quetrions. But i ca'nt remember how. Use vectors thingy with the cosine law and ****.

#4

its simple ballistics, right?

like, the arch thing, umm... factor in x and y movement of the ball, since its dropping as its going forwards, formulas for x require initial velocity, distance, time, and... something else, y formula needs gravity constant

as soon as i remember more, ill post again

like, the arch thing, umm... factor in x and y movement of the ball, since its dropping as its going forwards, formulas for x require initial velocity, distance, time, and... something else, y formula needs gravity constant

as soon as i remember more, ill post again

#5

s = vt

s = ViT + .5aT^2

110 = 40cos26t

solve for t

Plug t into

s = 40sin26t + .5at^2

Take vertical s (the one you just found) and

(s+1.2) - 3 = height above glove.

I didn't actually work it out as I don't have a calculator but follow that and see how it goes.

s = ViT + .5aT^2

110 = 40cos26t

solve for t

Plug t into

s = 40sin26t + .5at^2

Take vertical s (the one you just found) and

(s+1.2) - 3 = height above glove.

I didn't actually work it out as I don't have a calculator but follow that and see how it goes.

#6

find the horizontal speed and find how long it will take to get to the fielder. Then find out the initial vertical velocity and you can tell what the distance is by using the time from the first part. You have th VsubI being the vertical velocity after it was hit, Acceleration is -9.8m/s^2, and T is found from my first sentence. Throw the difference of the height of the hit and the fielders reach into that and it should work. I'd do the math, but im too lazy and its better for you to do it yourself anyway. Hope i helped!

#7

i hate physics, i have it right now, im such a history person.

#8

I'm quite the opposite of you, guitar infidel. I got a 96% in physics senior year and ~70% in history.

#9

Find the time for the ball to move 110m horizontalls remembering that there is no change in horizontal velocity (or at least that is assumed) and then find the height at which the ball is after same time moving vertically. I could work it out easily enough but its 4am and can't be bothered. Sorry.

#10

I always hated that horizontal acceleration was ignored. Granted, it minute, but i always thought horizontal was getting screwed over.

Edit: cool nibbler avatar.

Edit: cool nibbler avatar.

*Last edited by ilovecanada1121 at Sep 12, 2007,*

#11

wow, you guys are pretty smart.

i'm using the book and ur answers to figure it out.

thanks.

i'm using the book and ur answers to figure it out.

thanks.