#1

Alright, I serisouly need some help with this. I would be really thankful if someone did. And note that when I write *exponent* and some number, that number is supposed to be an exponent, I just couldn't figure how to do it on the pc. The pieces are as follows:

6(2x+1)(2x-1)+2x(x-3)*exponent2*-5x(3x-4)(3x+4) =

And I need to factorize this: 4*exponent3* + 8a*exponent2*b + 4ab*exponent2*

And it would be great if you could write down excactly how you figured it out, you know, the whole piece with all equacions and stuff. Thanks for all future replies

6(2x+1)(2x-1)+2x(x-3)*exponent2*-5x(3x-4)(3x+4) =

And I need to factorize this: 4*exponent3* + 8a*exponent2*b + 4ab*exponent2*

And it would be great if you could write down excactly how you figured it out, you know, the whole piece with all equacions and stuff. Thanks for all future replies

#2

So *exponent2* would equal e^2 or 2e?

#3

Alright, I serisouly need some help with this. I would be really thankful if someone did. And note that when I write *exponent* and some number, that number is supposed to be an exponent, I just couldn't figure how to do it on the pc. The pieces are as follows:

6(2x+1)(2x-1)+2x(x-3)*exponent2*-5x(3x-4)(3x+4) =

And I need to factorize this: 4*exponent3* + 8a*exponent2*b + 4ab*exponent2*

And it would be great if you could write down excactly how you figured it out, you know, the whole piece with all equacions and stuff. Thanks for all future replies

so (12x+6)(2x-1)

(24x squared -12) (12x-6) +2x(x-3)squared

(xsquared -3)

576 ( 6x-3)

omg i hate math i have no idea what exactly your doing but its basically doing that i think.

#4

Well, what I mean with *exponent2* and stuff, is that it's supposed to be like a small number behind a letter or number indictating how many times the letter is to be multiplied with itself.

Like a*eponent3* = aaa

4*exponent3* = 4 * 4* 4 = 64.

I'm sorry guys, but I'm norwegian xP

Like a*eponent3* = aaa

4*exponent3* = 4 * 4* 4 = 64.

I'm sorry guys, but I'm norwegian xP

#5

Well, what I mean with *exponent2* and stuff, is that it's supposed to be like a small number behind a letter or number indictating how many times the letter is to be multiplied with itself.

Like a*eponent3* = aaa

4*exponent3* = 4 * 4* 4 = 64.

I'm sorry guys, but I'm norwegian xP

Ohhh, I see! The best way to show that when you're typing is to do a^3=aaa

Your English is infinitely better than my Norwegian, so don't apologise!

#6

Alright

Well, thanks loads!!

Well, thanks loads!!

#7

Alright, I serisouly need some help with this. I would be really thankful if someone did. And note that when I write *exponent* and some number, that number is supposed to be an exponent, I just couldn't figure how to do it on the pc. The pieces are as follows:

6(2x+1)(2x-1)+2x(x-3)*exponent2*-5x(3x-4)(3x+4) =

And I need to factorize this: 4*exponent3* + 8a*exponent2*b + 4ab*exponent2*

And it would be great if you could write down excactly how you figured it out, you know, the whole piece with all equacions and stuff. Thanks for all future replies

6(4x^2 + 2x - 2x - 1) + 2x(x^2 - 3x - 3x + 9) - 5x(9x^2 - 16)

= (24x^2 - 6) + (2x^3 + 18x) - (45x^3 - 80x)

= -43x^3 + 24x^2 + 98x - 6

That's if you need to expand it. You didn't put a y so I assume it doesn't need solving.

Then with the other one

4^3 + 8a^2b + 4ab^2

= 4(4^2 + 2a^2b + ab^2)

= 4(4^2 + ab(2a + b))

= 4(16 + ab(2a + b))

I assume that's what you were after?

*Last edited by Snakexe at Sep 14, 2007,*

#8

6(4x^2 + 2x - 2x - 1) + 2x(x^2 - 3x - 3x + 9) - 5x(9x^2 - 16)

= (24x^2 - 6) + (2x^3 + 18x) - (45x^3 - 80x)

= -43x^3 + 24x^2 + 98x - 6

That's if you need to expand it. You didn't put a y so I assume it doesn't need solving.

Then with the other one

4^3 + 8a^2b + 4ab^2

= 4(4^2 + 2a^2b + ab^2)

= 4(4^2 + ab(2a + b))

= 4(16 + ab(2a + b))

I assume that's what you were after?

....I...I think so. I'm blindly going to follow the awesomeness of your math knowledge

Thanks alot!

#9

....I...I think so. I'm blindly going to follow the awesomeness of your math knowledge

Thanks alot!

No problem buddy! good old Maths A-level comes in handy once in a while..

#10

I will laugh when your asked how you got this answer *.... uhhhh UG.... I mean yeah UG*