#1

just a few questions i need help with coz i'm a dead****

1) An Electro motive force (EMF) of 10 volts was applied to a circuit and a current of 0.5A resulted. Calculate the circuits resistance.

2)An Electric Jug, which's heating element had a resistance of 100 ohms when operating, allowed a current of 2.4A to flow through it. Calculate the applied voltage.

3)When an ammeter was connected in series with a light globe, it indicated that a current of 0.1A was flowing through it. if the globes filament had a resistance of 1000 ohms when hot, calculate the applied voltage.

4) calculate the power dissipated by a 240volt light globe consuming 0.25A

there the ones i have left, i need all the formula's you used like V=IR and P=VI and that shiznit.

thanks for any help!

1) An Electro motive force (EMF) of 10 volts was applied to a circuit and a current of 0.5A resulted. Calculate the circuits resistance.

2)An Electric Jug, which's heating element had a resistance of 100 ohms when operating, allowed a current of 2.4A to flow through it. Calculate the applied voltage.

3)When an ammeter was connected in series with a light globe, it indicated that a current of 0.1A was flowing through it. if the globes filament had a resistance of 1000 ohms when hot, calculate the applied voltage.

4) calculate the power dissipated by a 240volt light globe consuming 0.25A

there the ones i have left, i need all the formula's you used like V=IR and P=VI and that shiznit.

thanks for any help!

#2

Why can't you do 'em yourself?

If people do it for you that's really not helping... you'll find it much harder in the exam room.

If people do it for you that's really not helping... you'll find it much harder in the exam room.

#3

Why can't you do 'em yourself?

If people do it for you that's really not helping... you'll find it much harder in the exam room.

well i clearly said that i cant do them myself coz i'm not smart enough, thats why i asked them to include the formulas and work so i could see what they did to get the answers

#4

1) You are given V (10 volts) and I (.5 amps). Which equation relates V to I? ....V=IR

Solve for R.

So, R=V/I

R=10/0.5=20 ohms

2) You are given R (100 ohms) and I (2.4 amps).

3) Given: R and I

4) You need to calculate power. The only equation that has power in it is: P=VI. You are given V and I.

Solve for R.

So, R=V/I

R=10/0.5=20 ohms

2) You are given R (100 ohms) and I (2.4 amps).

3) Given: R and I

4) You need to calculate power. The only equation that has power in it is: P=VI. You are given V and I.

*Last edited by ThatGuy45 at Sep 20, 2007,*

#5

Don't ya just love a nice CO poisonous gas alarm?

#6

1) You are given V (10 volts) and I (.5 amps). Which equation relates V to I? ....V=IR

Solve for R. So, R=V/I

2) You are given R (100 ohms) and I (2.4 amps).

3) Given: R and I

4) You need to calculate power. The only equation that has power in it is: P=VI. You are given V and I.

Listen to this guy.

Although there are plenty of other ways of working out power . EDIT: Unless he was referring to the ones you put in your original post, which I'm sure he was .

#7

So, all you are doing is rearranging those two equations and plugging in for the two variables that you know.

V is in volts

I is in amps

R is in ohms

P is in watts

V is in volts

I is in amps

R is in ohms

P is in watts

#8

It's piss easy. Would take, what, 3 minutes? Come on.