#1
just a few questions i need help with coz i'm a dead****

1) An Electro motive force (EMF) of 10 volts was applied to a circuit and a current of 0.5A resulted. Calculate the circuits resistance.

2)An Electric Jug, which's heating element had a resistance of 100 ohms when operating, allowed a current of 2.4A to flow through it. Calculate the applied voltage.

3)When an ammeter was connected in series with a light globe, it indicated that a current of 0.1A was flowing through it. if the globes filament had a resistance of 1000 ohms when hot, calculate the applied voltage.

4) calculate the power dissipated by a 240volt light globe consuming 0.25A


there the ones i have left, i need all the formula's you used like V=IR and P=VI and that shiznit.

thanks for any help!
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#2
Why can't you do 'em yourself?

If people do it for you that's really not helping... you'll find it much harder in the exam room.
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#3
Quote by Hobolad
Why can't you do 'em yourself?

If people do it for you that's really not helping... you'll find it much harder in the exam room.



well i clearly said that i cant do them myself coz i'm not smart enough, thats why i asked them to include the formulas and work so i could see what they did to get the answers
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#4
1) You are given V (10 volts) and I (.5 amps). Which equation relates V to I? ....V=IR
Solve for R.
So, R=V/I
R=10/0.5=20 ohms

2) You are given R (100 ohms) and I (2.4 amps).

3) Given: R and I

4) You need to calculate power. The only equation that has power in it is: P=VI. You are given V and I.
Last edited by ThatGuy45 at Sep 20, 2007,
#6
Quote by ThatGuy45
1) You are given V (10 volts) and I (.5 amps). Which equation relates V to I? ....V=IR
Solve for R. So, R=V/I

2) You are given R (100 ohms) and I (2.4 amps).

3) Given: R and I

4) You need to calculate power. The only equation that has power in it is: P=VI. You are given V and I.



Listen to this guy.


Although there are plenty of other ways of working out power . EDIT: Unless he was referring to the ones you put in your original post, which I'm sure he was .
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#7
So, all you are doing is rearranging those two equations and plugging in for the two variables that you know.

V is in volts
I is in amps
R is in ohms
P is in watts
#8
It's piss easy. Would take, what, 3 minutes? Come on.
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