#1
Okay i have a man cold and i'm confused by this so eah i've turned to UG

I'll just '/' to expressed square root signs

I have to express each of these in the form k /5
And i have /63 and 21 over /7

Any help? And then i have to hence write /63 + 21 over /7 in the form n /7 - which is 6 /7 but with the first bit i am lost

I'm mega confused
Last edited by philipisabeast at Sep 30, 2007,
#2
/63

= /9 * /7

=3/7

Easy enough

and 21 over /7

This one is harder, you have to rationalise the denominator. The only way to make /7 a rational number is to multiply it by /7.

So multiply 21 over /7 by /7 over /7

Then you will get 21/7 over 7 which will cancel down to 3/7 over 1, therefore 3/7 = answer.
#4
Quote by Mattmakesmetal
^^^ *stabs in the face*


I was so going to say that..


Quote by wiggyisgreat
Slooj, I'd bang you so hard.


••The Robin Trower Fans Group••
PM me to join!
#6
Laff it's AS but i had to give it in the form k /5 - he gave it in 7? Or is the question in fact sneaky?
#7
Quote by philipisabeast
Laff it's AS but i had to give it in the form k /5 - he gave it in 7? Or is the question in fact sneaky?

Good point. Tell you what, I am doing some maths homework right now so I will have a blast at this mofo. Just wait for my edit.

EDIT 1: I have just found that 21 /7 over /7 (which we have already established to be 3 /7 goes to /9 /7 which goes to /63 so you essentially have /63 + /63 here.

EDIT 2: 63 into 5? wtf? This question phails to the root of epic.
Last edited by MadClownDisease at Sep 30, 2007,
#8
Quote by MadClownDisease
AS level maths ftw!


I'm having to do this at GCSE!
I play by my own rules. And I have one rule; There are no rules... but if there are, they're there to be broken. Even this one.


Confused? Good.

Quote by CrucialGutchman
Sigs are wastes of my precious screen space.

^ Irony

Quote by RevaM1ssP1ss
LET ME HUMP YOU DAMMIT
#10
Quote by bequickorbedead
The A-level ones aren't much harder...


Yeah but I suck at maths. And there's no way I'll take it for A level.
I play by my own rules. And I have one rule; There are no rules... but if there are, they're there to be broken. Even this one.


Confused? Good.

Quote by CrucialGutchman
Sigs are wastes of my precious screen space.

^ Irony

Quote by RevaM1ssP1ss
LET ME HUMP YOU DAMMIT
#11
Quote by MadClownDisease


EDIT 2: 63 into 5? wtf? This question phails to the root of epic.


haha

I'll just leave it
#12
Quote by MadClownDisease
AS level maths ftw!



I don't recall doing surds at AS level.
Co-President of UG's Tubgirl Virgins Club

#13
I just started my AS course and surds in in teh first unit...
Quote by cakemonster91

*chuckle* A peanut. With a face.



Go to your staff paper and re-write this song a half step down so on the paper it'll be like you have a "C" just move it down to a "B#"




Know your theory, then play like you don't.

#15
We havent touched on them at AS yet, but we have done them before in maths.

I'll have a go at these two though. Though the √63 one seems a bit odd
Double Neck Project - Winner of 2006 GB&C "Best guitar build from scratch", "(Best) Most expensive build" and "Best Idea" awards - FINISHED!

Member #2 of the UG Luthier's club. PM AlGeeEater to join.
#16
I got a result but its a bit of a crap way to do it. (I did it in my head, so it might be wrong, but then again, C1 is non-calculator anyway)

√63 = √(3/5)*√105
= √(15/25)*√105
= √(15/25)*√21*√5
= √(315/25)*√5
= (√315)/5*√5
Double Neck Project - Winner of 2006 GB&C "Best guitar build from scratch", "(Best) Most expensive build" and "Best Idea" awards - FINISHED!

Member #2 of the UG Luthier's club. PM AlGeeEater to join.
#17
was wrong again.
this should be correct
√63+21 / √7
3√7+21 / √7
(3√7(√1/5)(√5))+(21(√1/5)(√5)) / √7
eliminate (√5) to find k
therefore k = (21√(1/5)+3√(7/5)) / √7
Last edited by xtremebigbird at Sep 30, 2007,