#1
Hey guys, iv got a couple of issues with math for a project tomorrow

the questions :
Evaluate the following:

3^2 + 2^0 + 3^-2
___________________
3 - 3^-1


(64^1/6)(27^2/3)


(27/125)^-2/3


when i put the ^ i mean to the power of
and when its something like 2/3 its a fraction

so in the last question its 27 over 125 to the power of negative 2 over 3


please guys any serious help would be appreciated

thanks alot guys
#2
if there's 2^0 then its not a real number. put no real answer unless you know how to use imaginary numbers
#3
11.

3^2 (9) + 2^0 (1) + 3^-2 (1).

9+1+1=11.

There you go


Edit: sobeisbull, you don't have to use imaginary numbers- anything to the power of zero is one.

Extra Edit: I completely misread this the first time. oops.
Oh wait, I'm still right. It's 11.
So good to see you once again.
I thought that you were hiding.
And you thought that I had run away.
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Last edited by Sapient at Oct 15, 2007,
#4
Any scientific calculator can do these. Even the calculator on your computer can do them.


I'll have a bourbon.
#5
when an exponent is negative, it just means that u put a one over the number

ex. 3^-2 = 1/(3^2)

when an exponent is fractional, it means radical of

ex. 3^(1/2) = (radical sign)3

Hope this helps
#6
so even though its in a fraction there is no answer?

3^2 + 2^0 + 3^-2
___________________
3 - 3^-1

= No real answer?
#8
Oh, I did do it wrong. Backtothe was right. it's 1/9. and 3^-1 is 1/3. Ignore that first post.
So good to see you once again.
I thought that you were hiding.
And you thought that I had run away.
Chasing the tail of dogma.
I opened my eye and there we were .
#9
Jesus, you're not very smart are you?

Type it into a Google prompt. It will give you the answer.
Looking for my India/Django.
#10
well i appologise for coming across as "not very smart" math has never been my thing but thank you
#11
Quote by sobeisbull
if there's 2^0 then its not a real number. put no real answer unless you know how to use imaginary numbers


anything to the power of zero is actually 1
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