I'm doing my trig HW and I've got to find the exact valua (implying not using a calculator) of

Arccos (square root 3 / 2)

Now I know this is one of the common coordinates on the unit circle but I don't really understand what the question is asking and how to solve. Am I supposed to be finding a value for theta or what? Thanks in advance.
Quote by tunasband
Who's ug?
What angle gives the cos value of root 3/2? That's all it is asking.

You need to understand the unit circle to figure that out.
Quote by Altered_Carbon
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