I have this problem

e^(x*y) = 2^y - 4^x

how do I find the derivate of this? I know I have to use a natural logs but Im not sure how to solve it.. thx in advance!
ew gawd i hated calc. i'm glad i never have to take math again. woot for english major.

ummm i thinkkk you

no crap i have no idea i havnt done this in like 2 years, sorry bro i feel your pain.
I can tell you that;

x*y = ln(2^y - 4^x)

Whether or not that's any help I don't know.


Oh, from there;

x*y = ln2^y - ln4^x

x*y = yln2 - xln4

Still not sure where it's going though
Co-President of UG's Tubgirl Virgins Club

It's implicit differentiation. The answer is

dy/dx = (-ln(x)*4^x - y*e^(x*y)) / (e^(x*y) - ln(y)*(2^y)).

Thanks for making me do that. I haven't done simple calc in over a year. Now someone get me a hard multivariable calc problem.

EDIT: I f*cked up. It should be -ln(x)*4^x. If you saw the unfixed version, it's fixed now.
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Last edited by darkstar2466 at Oct 18, 2007,