#1
alright you guys have never failed me on math problems before so here goes.
a plane is 5000 miles away and coming in at 700mph.
after 15 mins, an interceptor is sent towards it at 800mph.
how long will it take them to meet?
if anyone could point me in the right direction (ie what equation to use) I would me grateful. lulz
#2
distance speed and time i think?

Edit: but dont take my word for it, you may want to wait for someone else first.
LEAFS FOR CUP
#3
distance is a function of time
s = v * t

write down the distance for both the plane and the interceptor (take the "after 15 minutes" as having the time as "t-15min")

then make distance plane = distance interceptor and solve for time


edit: wait, its coming from the other direction
in which case just put a negative velocity for one of them and figure a way to put that 5000 miles away in there
#4
Quote by seljer
distance is a function of time
s = v * t

write down the distance for both the plane and the interceptor (take the "after 15 minutes" as having the time as "t-15min")

then make distance plane = distance interceptor and solve for time


edit: wait, its coming from the other direction
in which case just put a negative velocity for one of them and figure a way to put that 5000 miles away in there

that sounds about right to me
Gear:
Jackson DKMG Dinky (EMG 81/85)
Ibanez GIO (i put a Dimbucker in the bridge)
Crate GT65 (65 watts) to be upgraded soon, suggestions welcome (must be tubed)
Floor Pod (for sale)
#7
Quote by ygokazuki
s = v*t?
what do s and v stand for?


s is position
v is velocity
Quote by garrett5
"An Iron Curtain has descended over our classroom..."

Quote by FlippinSweet
You look at too much porn and have unfortunatley contracted an e-STD
#8
s is distance, v is velocity
Quote by The Postman
Usually emos, have like twiggy legs you can snap in your hands...
Has anyone ever seen an obese emo?

Quote by cool#9
Whose fault is it you are a skinny worthless wimp, be a fat emo, problem solved.
#9
location of plane = 5000miles - 700mph * t
location of interceptor = 800mph * (t - 15min)

5000miles - 700mph * t = 800mph * (t - 15min)

5000miles - 700mph * t = 800mph * t - 200miles
t * 1500 mph = 5200 miles
t= 5200 miles/1500 mph = 3.47 hours

you suck at math/physics
#11
dude i didnt expect any one to know on this site holy sh!t ,
Quote by RizzoWashburn
Oh, and this is the internet. I have the right to be a douchebag. Fuck off.
#12
Ok, basically plane is 5000 miles away...it travels at 700mph for 15 mins, therefore the distance it travels before the interceptor is sent is 700 / 4 = 175

so plane is 5000 - 175 = 4825 miles away when the interceptor is sent.

The interceptor is 4825 miles away when it is sent and travels at 800 mph.

the planes are travelling towards each other so you have 800 and 700 mph as the speeds, which combine to make 1,500 mph the speed at which the distance between the planes decreases.

So you divide 4825 by 1500 and that gives you 3.216 (recurring 6) hours, or roughly 3 hours and 12 minutes til the planes meet


Edit: Or so I thought lol It seems I am wrong then probably, as seljer appears to know what he is doing
#13
actually your answer is right too
except its the time from the when interceptor sets off (so -0.25 hours off my answer)
#14
Ah I'm glad to hear I'm not losing my mind slowly since finishing school and not having to study maths (before someone calls me stupid, in the UK we call it maths - short for mathematics, so I'll spell it my way, and you spell it yours) and physics ever again
#15
leik aljabra was so fun in leik midal skool
Quote by denizenz
I'll logic you right in the thyroid.

Art & Lutherie