#1

sorry for the "scary words"

What should I do here?

(X2+7x-5) / X-2

would it be X2/X = X and 7x/X= 7 and then bring down the -5 and /-2

?

the X2 is X to the 2nd power

thanks

I left class during the lesson so I didn't have any notes

What should I do here?

(X2+7x-5) / X-2

would it be X2/X = X and 7x/X= 7 and then bring down the -5 and /-2

?

the X2 is X to the 2nd power

thanks

I left class during the lesson so I didn't have any notes

#2

When did they start adding the alphabet to math?!?!?!?!?!?

#3

When did they start adding the alphabet to math?!?!?!?!?!?

/generic

#4

x^2 + 7x - 5 / x-2

The coefficient on x^2 is 1, so multiply x-2 by x => x^2 - 2x

Now subtract that from x^2 + 7x - 5 to get 11x - 5.

The coefficient of the x term is 11, so multiply x - 2 by 11 => 11x - 22

Now subtract that from 11x - 5 to get 17, so 17 is your remainder and your quotient is x + 11.

Your answer for x^2 + 7x - 5 / x - 2 = x + 11 + (17/x-2) (if you don't know how I got the 17/x-2, please go ahead and kill yourself.)

The coefficient on x^2 is 1, so multiply x-2 by x => x^2 - 2x

Now subtract that from x^2 + 7x - 5 to get 11x - 5.

The coefficient of the x term is 11, so multiply x - 2 by 11 => 11x - 22

Now subtract that from 11x - 5 to get 17, so 17 is your remainder and your quotient is x + 11.

Your answer for x^2 + 7x - 5 / x - 2 = x + 11 + (17/x-2) (if you don't know how I got the 17/x-2, please go ahead and kill yourself.)

#5

/generic

Well SOOORRRRYYYY!!! Mister GRRR-Man I'm tired and not on the top of my game.

#6

x^2 + 7x - 5 / x-2

The coefficient on x^2 is 1, so multiply x-2 by x => x^2 - 2x

Now subtract that from x^2 + 7x - 5 to get 11x - 5.

The coefficient of the x term is 11, so multiply x - 2 by 11 => 11x - 22

Now subtract that from 11x - 5 to get 17, so 17 is your remainder and your quotient is x + 11.

Your answer for x^2 + 7x - 5 / x - 2 = x + 11 + (17/x-2) (if you don't know how I got the 17/x-2, please go ahead and kill yourself.)

STOP TALKING LIKE THAT!

lol

I was checking the book and it stated that I would divid the X2 and 7X by the X and then get the answer

then bring down the -5 and add to the 7

getting 2

then divide that by the -2 and get -1

the problem is as follows

(X2+ 7x -5)

(X2+ 7x -5)

X-2

#7

I sound like a book, don't I? I authored an Algebra curriculum for a tutoring place this summer. I'll make a ****ty paint drawing for you and that should clear it up. Wait up for a few minutes.

#8

I messed up. It should be 9x, not 11x. Sorry about that.

#9

I sound like a book, don't I? I authored an Algebra curriculum for a tutoring place this summer. I'll make a ****ty paint drawing for you and that should clear it up. Wait up for a few minutes.

Thanks. Hopefully I can make a connection to the rest of the lesson lol

#10

Did you see the paint thing?

#11

#12

Did you see the paint thing?

Yeah but the next problem is hard.

I didn't really understand what happened with the X^2 and how you got -18

I figure it was from the -2 in the dividend multiplied by the 9

but I'm not good at algebra

the problem I'm on

is

3X^2+11X+1

3X^2+11X+1

X-3

and I have 14X+3 as the remainder but I don't how to get the rest of the problem.

I got rid of 3X^2 and add -3X to 11X to get 14X and multiplied the 1 by 3

#13

That's the last of the help you'll get from me. I have a life to attend to now, go shower, make dinner, go out etc.

#14

That's the last of the help you'll get from me. I have a life to attend to now, go shower, make dinner, go out etc.

Thanks

Did you use FOIL?

*Last edited by TDKshorty at Nov 9, 2007,*

#15

I always liked synthetic division better.

since it is (X2+7x-5) / X-2

do the following:

1. line the coefficients up starting from the highest degree to the lowest

ex. 1 | 7 | -5

2. take the 2 out of the x-2 and put it to the left like so:

_ 1 | 7 | -5

2 |

3. bring the first coeff. straight down

_1 | 7 | -5

2 |

_1 |

4. multiply the 2 by the number that you brought down, then put the product directly below the next coeff. then addthe product from the coeff and bring that number straight down.

_1 | 7 | -5

2 | 2 |

_1 | 9 |

then repeat for the 9

_1 | 7 | -5

2 | 2 | 18

_1 | 9 | 13

finally put the all of the bottom numbers next to an X starting with the highest degree - 1 (X2 turns into X) and the last number is the remainder

you should now have:

X + 9

----------- or X+9 with a remainder of 13

13

sorry darkstar but i think you almost had it

since it is (X2+7x-5) / X-2

do the following:

1. line the coefficients up starting from the highest degree to the lowest

ex. 1 | 7 | -5

2. take the 2 out of the x-2 and put it to the left like so:

_ 1 | 7 | -5

2 |

3. bring the first coeff. straight down

_1 | 7 | -5

2 |

_1 |

4. multiply the 2 by the number that you brought down, then put the product directly below the next coeff. then addthe product from the coeff and bring that number straight down.

_1 | 7 | -5

2 | 2 |

_1 | 9 |

then repeat for the 9

_1 | 7 | -5

2 | 2 | 18

_1 | 9 | 13

finally put the all of the bottom numbers next to an X starting with the highest degree - 1 (X2 turns into X) and the last number is the remainder

you should now have:

X + 9

----------- or X+9 with a remainder of 13

13

sorry darkstar but i think you almost had it

#16

^ Oh, my bad. - (-13) is positive. You are right sir, I concede. My work on the second problem is right though.

#17

yes. I must agree.

"Astounding work super math team!"

now, off to bed for me!

"Astounding work super math team!"

now, off to bed for me!

#18

Darkstar

one more thing?

on the X-3 x 3X

did you use FOIL to get the 9x?

one more thing?

on the X-3 x 3X

did you use FOIL to get the 9x?

#19

No man, it's multiplying a single term with two terms, so you just distribute. Example:

a(b+c) = ab + ac

3x (x - 3) = 3x(x) + 3x(-3)

= 3x^ - 9x

a(b+c) = ab + ac

3x (x - 3) = 3x(x) + 3x(-3)

= 3x^ - 9x

#20

No man, it's multiplying a single term with two terms, so you just distribute. Example:

a(b+c) = ab + ac

3x (x - 3) = 3x(x) + 3x(-3)

= 3x^ - 9x

Alright thanks,

I understand it when its taught to me but I can't apply it.

EDIT:

So

2x^2+3x-1

2x^2+3x-1

X+4

= 2x +11 + (4/X+4)

?

If so then I've got it

*Last edited by TDKshorty at Nov 9, 2007,*