#1
Oj guys, I need some help with this math project. I need to find the phase shift and vertical shift of three trigonometric equations. I don't know if I'm doing these right so that's why I came on here. The pi doesnt look right on heree but i'll try it anyways (its going to be π for pi) ok here they are...


y= 3 sin (2x+π/4)

y= .5 cos (4x-π+1

y= -2 sec .5x

Please help!
Quote by schecter_elite
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#2
shifting from what? the normal equations:

y=sin x
y=cos x
y= sec x

?

more specific please.
"And after all of this, I am amazed...

...that I am cursed far more than I am praised."
#3
I guess, all it says on the paper is what I said....but that's what I was thinking.
Quote by schecter_elite
But yeah, do some moshing at a fall out boy concert, it's fricken awsome.
#4
Quote by roshiee

y= 3 sin (2x+π/4)

ok, sin (2x) means there's going to be twice as many cycles, ie. sin repetes after pi, rather than 2 pi.

+ pi/4 in the bracket means you shift the graph left by pi/4 (i think)

3 of every thing means the graphs limits at 3 and -3, rather than 1 and -1.

y= .5 cos (4x-π+1

see: above except now its (4x) rather than (2x) and .5 rather than 3. the -pi means shift the graph to the right by pi.

and the +1 at the end means the whole graph is shifted up 1, so it limits at 0 and 2, rather than 1 and -1.

y= -2 sec .5x

simpler version of the above


enjoy.
"And after all of this, I am amazed...

...that I am cursed far more than I am praised."
#5
So for the first one, the vertical shift would be 3?
Quote by schecter_elite
But yeah, do some moshing at a fall out boy concert, it's fricken awsome.
#6
it doesn't shift vertically. it stretches.
"And after all of this, I am amazed...

...that I am cursed far more than I am praised."
#7
So what should I put for vertical shift? 0?
Quote by schecter_elite
But yeah, do some moshing at a fall out boy concert, it's fricken awsome.
#8
i honestly don't know what your questions mean either.
"And after all of this, I am amazed...

...that I am cursed far more than I am praised."