#1

A nonconducting disk of radius a lies in the z = 0 plane with its center at the origin. The disk is uniformly charged and has a total charge Q. Find Ez on the z axis at the following positions. (Assume that these distances are exact.)

Let: z = a find answer with these units: Q / (a2ε0)

Can anyone point me in the right direction?

Perhaps this equation may need to be used... not sure though: sqrt((1/3)R^2)

Let: z = a find answer with these units: Q / (a2ε0)

Can anyone point me in the right direction?

Perhaps this equation may need to be used... not sure though: sqrt((1/3)R^2)

#2

Up, Up, Down, Down, Left, Right, Left, Right, B, A, B, A, START

#3

You'll need Coulomb's Law

And, hey presto, you're done

Well done, that was useful

And, hey presto, you're done

Up, Up, Down, Down, Left, Right, Left, Right, B, A, B, A, START

Well done, that was useful

#4

THanks.

#5

So if... (a) z = 0.2a wouldnt the answer be 1.989 Q / (a2ε0) ?

#6

Up, Up, Down, Down, Left, Right, Left, Right, B, A, B, A, START

+infinity

You win.

Im gunna sig that!

#7

+infinity

You win.

Im gunna sig that!

There is no equation that can't be solved with the Konami Code.

#8

Up, Up, Down, Down, Left, Right, Left, Right, B, A, B, A, START

Konami Code?

#9

So if... (a) z = 0.2a wouldnt the answer be 1.989 Q / (a2ε0) ?

I got that, so I think so :P

The disc can be treated as a point charge Q at the origin if the force is being calculated perpendicularly from the centre.

#10

Konami Code?

I just dated myself with my Konami reply so bad...

#11

I got that, so I think so :P

The disc can be treated as a point charge Q at the origin if the force is being calculated perpendicularly from the centre.

Hm... not working. Maybe it's a different equation or maybe I'm just doing it wrong... seems to make sense though.