#1
How do you find the inverse of a logarithm? Explain to me with y=log7 49x. The 49 is to the x power btw.
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#3
to find out what log 7 is (is it long base 10?) it would be log7/long10 then its a simple algebra problem, I think its a change of base formula
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#4
ummm thats totaly wrong to what my book says
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#5
y = log7 49x

the inverse should be

49^x = 7 ^ y (49 to the x power = 7 to the y power)

49 = 7² so

7^²x = 7^y

2x = y